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3 years ago

How to find the length of EF?

Mathematics

2 answers:

nika2105 [10]3 years ago

8 0

$CD = \frac{HG + EF}{2} \Leftrightarrow EF = 2CD - HG$

$2x - 2 = 2x - x + 3\\2x - 2x + x = 3 + 2\\x = 5$

$EF = 2 * 5 - 2 = 10 - 2 = 8$

Answer: 8.

slava [35]3 years ago

8 0

Answer:

EF=8

Step-by-step explanation:

HG=x-3

CD=x

EF=2x-2

Since HG is 3 less than CD, EF has to be 3 more than CD

x+3=2x-2

3+2=2x-x

5=x

x=5

HG=2

CD=5

EF=8

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