Answer:
When balloon moves in the downward direction two forces acts on it.
i) Force exerted by air in the upward direction
ii) Weight
According to newton’s second law of motion:
Sum of forces = Ma
W – F = Ma
Mg – F = Ma …….. (i)
when some of the mass m is dropped and balloon is moving in upward direction with acceleration a/2 then,
F – W = (M-m)a/2
F – (M-m)g = (M-m)a/2
F – Mg + mg = Ma/2 – ma/2 ….. (ii)
Adding equation (i) and (ii)
mg = M(3a/2) – ma/2
m(g + a/2) = M(3a/2)
m = M(3a/2)/(g + a/2)
He got u too bad for the late reply to the question I have;)
I don’t understand can you please explain your question thank u
Answer:
r = 255.68 m
Explanation:
When a body moves in a circular path, an acceleration, due to constant change in its direction, is developed, known as centripetal acceleration. The centripetal acceleration acts towards the center of the circular path. The formula to calculate the centripetal acceleration is given as follows:
ac = v²/r
where,
ac = centripetal acceleration = 22 m/s²
v = tangential speed = 75 m/s
r = radius of curve = ?
Therefore,
22 m/s² = (75 m/s)²/r
r = (75 m/s)²/(22 m/s²)
<u>r = 255.68 m</u>
