The ability of a measurement to be reproduced with the same result is a sign of accuracy
2 answers:
Answer:
False
Explanation:
<em>Accuracy vs precision.</em>
In the field of science in general, precision is the ability of an instrument to obtain the same result in different measurements, developed under the same conditions. On the other hand for statistics, engineering, or science in general, accuracy is the ability of an instrument to measure a value close to the actual magnitude.
Take a look at the picture I attached you. From left to right:
1. Low accuracy, Low precision
2. High precision, Low accuracy
3. High accuracy, low precision
4. High accuracy, High precision
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Answer:
(a) 51428.59 J/C
(b) 25714.29 J/C
(c) 0 J/C
Explanation:
Parameters given:
Q1 = 2 * 10^-6 C
Q2 = 2 * 10^-6 C
Q3 = 2 * 10^-6 C
Q4 = 2 * 10^-6 C
=> Q1 = Q2 = Q3 = Q4 = Q
Side of the square = 2m
The center of the square is the midpoint of the diagonals, i.e. Using Pythagoras theorem:
BD² = 2² + 2²
BD² = 8
BD = √(8) = 2.8m
OD = 1.4m
(The attached diagram explains better)
Hence, the distance between the center and each point charge, r, is 1.4m.
Electric Potential, V = kQ/r
k = Coulombs constant
(a) If all charges are positive:
V(Total) = V1 + V2 + V3 + V4
V1 = Potential due to Q1
V2 = Potential due to Q2
V3 = Potential due to Q3
V4 =Potential due to Q4
Since Q1 = Q2 = Q3 = Q4 = Q
=> V1 = V2 = V3 = V4
=> V(Total) = 4V1
V = (4 * 9 * 10^9 * 2 * 10^-6)/1.4
V = 51428.59J/C
(b) If 3 charges are positive and 1 is negative:
Since Q1 = Q2 = Q3 = Q
and Q4 = -Q
The total potential becomes:
V(Total) = V1 + V2 + V3 - V4
Since V1, V2, V3 and V4 have the same value,
V(Total) = V1 + V2
V(Total) = 2V1
V(Total) = (2 * 9 * 10^9 * 2 * 10^-6)/1.4
V(Total) = 25174.29 J/C
(c) Two charges are positive and two are negative:
Since Q1 = Q2 = Q
and Q3 = Q4 = -Q
The total potential becomes:
V(Total) = V1 + V2 - V3 - V4
Since V1, V2, V3 and V4 have the same value,
V(Total) = 0 J/C
