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Serggg [28]
3 years ago
12

Please help .thanks

Mathematics
2 answers:
Yuki888 [10]3 years ago
5 0

Answer:

2 and 1/5 is greater than 2.15

Step-by-step explanation:

This is true because 1/5 is equal to .20 which is greater than .15

FromTheMoon [43]3 years ago
4 0

Answer:

B, >

Step-by-step explanation:

2 1/5

2*5= 10+1= 11

11/5 vs 2.15

2.2 vs 2.15

2.2 > 2.15

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What is the solution for x? 9-x/5=3
navik [9.2K]

Answer:

x = 30

Step-by-step explanation:

9-x/5=3

Subtract 9 from each side

9-9-x/5=3-9

-x/5 = -6

Multiply each side by -5

-x/5 *-5 = -6*-5

x = 30

8 0
3 years ago
Read 2 more answers
Apply the laws of exponents, calculate the result and express the result in scientific notation, and as a decimal: (8.1*10^-4)^2
AfilCa [17]
<h3>Answer:</h3>
  • the result in scientific notation is 6.561×10⁻⁷
  • the result as a decimal is 0.000 000 656 1
<h3>Explanation:</h3>

The rules of exponents say the exponent outside parentheses applies to each factor inside parentheses.

... (8.1*10^-4)^2 = 8.1^2 × (10^-4)^2

... = 65.61 × 10^-8

... = 6.561 × 10^-7 . . . . adjust to scientific notation with one digit left of the decimal point

The exponent of -7 means the decimal point in the decimal number is 7 places to the left of where it is in scientific notation. That is ...

... 6.561 × 10^-7 = 0.0000006561

4 0
3 years ago
A pair of boots are $95.00 and are on sale for 30% off. What is the sale price of the boots?
polet [3.4K]

Answer:

$66.50, and you saved $28.50

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Dubnium-262 has a half-life of 34 s. How long will it take for 500.0 grams to
dmitriy555 [2]

Answer:

the time taken for the radioactive element to decay to 1 g is 304.8 s.

Step-by-step explanation:

Given;

half-life of the given Dubnium = 34 s

initial mass of the given Dubnium, m₀ = 500 grams

final mass of the element, mf = 1 g

The time taken for the radioactive element to decay to its final mass is calculated as follows;

1 = 500 (0.5)^{\frac{t}{34}} \\\\\frac{1}{500} =  (0.5)^{\frac{t}{34}}\\\\log(\frac{1}{500}) = log [(0.5)^{\frac{t}{34}}]\\\\log(\frac{1}{500})  = \frac{t}{34} log(0.5)\\\\-2.699 = \frac{t}{34} (-0.301)\\\\t = \frac{2.699 \times 34}{0.301} \\\\t = 304.8 \ s

Therefore, the time taken for the radioactive element to decay to 1 g is 304.8 s.

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2 years ago
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