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Serggg [28]
3 years ago
12

Please help .thanks

Mathematics
2 answers:
Yuki888 [10]3 years ago
5 0

Answer:

2 and 1/5 is greater than 2.15

Step-by-step explanation:

This is true because 1/5 is equal to .20 which is greater than .15

FromTheMoon [43]3 years ago
4 0

Answer:

B, >

Step-by-step explanation:

2 1/5

2*5= 10+1= 11

11/5 vs 2.15

2.2 vs 2.15

2.2 > 2.15

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Katie has read 32% of a book. if she has read 80 pages, how many more pages does Katie have left to read?
Blababa [14]
Katie has read 32%, so 32%=80 pages. To get the total number of pages, you have to divide 32 and 80 by 8 to get 4% and 10 pages. 4% of the book is 10 pages, and in order to get 100%, you have to multiply by 25(4*25=100) on both sides. Remember, what you do to one side, you do to the other side. That leaves you with 100% and 250 pages. The book is 250 pages long. If she  has read 80 pages, you subtract 80 from 250 to find how many pages she has left to read. The difference is 170. Katie has 170 pages left to read.
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3 years ago
F = (4x-3)au carre - (x+3)(3-9x)
Vinvika [58]

Answer:

<em>Translater</em>

Step-by-step explanation:

<em>F = (4x-3) squared - (x + 3) (3-9x)</em>

<em>- develop and reduce (4x-3) to the edge</em>

<em>- show that F = (5x) squared</em>

<em />

  • <em>(NOT AN ANSWER ITS TO HELP OTHERS WHO DOESN"T KNOW FRENCH)</em>
7 0
2 years ago
H(2) = 3.c +3<br> g(x) = -4x+1<br> Find (h+g) (10)
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3 years ago
Katrina wants to estimate the proportion of adults who read at least 10 books last year. to do​ so, she obtains a simple random
Vaselesa [24]
E=Z*sqrt (p(1-p)/N), where E= error margin, p=proportion, N=sample size

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Mathew's margin error at 99% confidence interval: E= 2.58*sqrt (p(1-p)/400) = 0.129 sqrt (p(1-p))

Since both obtained same estimate of proportion (that is, value of p), it can be seen that Mathew's estimate will have a small error (That is, 0.129 is smaller than 0.196). This can be attributed to larger sample size although a wider confidence (99%) interval was considered.
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3 years ago
PLEASE HELPP MEE!!!!
Artemon [7]

does the answer help you.

5 0
2 years ago
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