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3 years ago

The law of conservation of momentum states that (Help Asap!)

Physics

1 answer:

bezimeni [28]3 years ago

6 0

The law of conservation states that the total amount of energy of an isolated system remains constant; it is said to be conserved over time

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What happens when red, blue, and green light come together?

Alja [10]

Answer:

I believe if red, blue, and green light come together it would produce White light.

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2 years ago

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During an all-night cram session, a student heats up a 0.607 liter (0.607 x 10- 3 m3) glass (Pyrex) beaker of cold coffee. Initi

mina [271]

Answer: 0.00000938422m^3

Explanation:

dV=Vø*β*(t1-tø)

The parameters are

dV is the change in volume after temperature increase

Vø =0.607 *10^-3m3 is the initial vokume of coffe at 16.2^0 C

β= coefficient of volume expansion of water at 16.2^0 C is 0.0002/0C

t1= 93.5^0C final temperature

tø=16.2^0 C

Therefore

dV=0.607 *10^-3 *0.0002*(93.5-16.2)

dV= 0.00000938422m^3

This is the volume of coffee that will spill over the container

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3 years ago

Which substance is a compound Li, N2, H2, CO2?

kupik [55]

Carbon dioxide is a compound (CO2). The other are just considered molecules since they are bonded to themselves. Lithium (Li) is an element since it's on its own and hasn't formed a bond yet.

6 0

4 years ago

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A 782-kg satellite is in a circular orbit about Earth at a height above Earth equal to Earth's mean radius. (a) Find the satelli

Vadim26 [7]

Answer:

a) v = 5.59x10³ m/s

b) T = 4 h

c) F = 1.92x10³ N

Explanation:

a) We can find the satellite's orbital speed by equating the centripetal force and the gravitation force as follows:

$F_{c} = F_{G}$

$\frac{mv^{2}}{r + h} = \frac{GMm}{(r + h)^{2}}$

$v = \sqrt{\frac{gr^{2}}{r+h}$

Where:

g is the gravity = 9.81 m/s²

r: is the Earth's radius = 6371 km

h: is the satellite's height = r = 6371 km

$v = \sqrt{\frac{gr^{2}}{2r}} = \sqrt{\frac{gr}{2}} = \sqrt{\frac{9.81 m/s^{2}*6.371 \cdot 10^{6} m}{2}} = 5.59 \cdot 10^{3} m/s$

b) The period of its revolution is:

$T = \frac{2\pi}{\omega} = \frac{2\pi (r + h)}{v} = \frac{2\pi (2*6.371 \cdot 10^{6} m)}{5.59 \cdot 10^{3} m/s} = 14322.07 s = 4 h$

c) The gravitational force acting on it is given by:

$F = \frac{GMm}{(r + h)^{2}}$

Where:

M is the Earth's mass = 5.97x10²⁴ kg

m is the satellite's mass = 782 kg

G is the gravitational constant = 6.67x10⁻¹¹ Nm²kg⁻²

$F = \frac{GMm}{(r + h)^{2}} = \frac{6.67 \cdot 10^{-11} Nm^{2}kg^{-2}*5.97 \cdot 10^{24} kg*782 kg}{(2*6.371 \cdot 10^{6} m)^{2}} = 1.92 \cdot 10^{3} N$

I hope it helps you!

3 0

3 years ago

Two 2.0-mm diameter beads, C and D, are 12mm mm apart, measured between their centers. Bead C has mass 1.0 g and charge 2.5nC nC

Artist 52 [7]

Answer:

Explanation:

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3 years ago