Answer:s=0.68 m
Explanation:
Given
Inclination 
Speed of block(u)=1.6 m/s
Coefficient of kinetic Friction 
deceleration provided by friction=g\sin \theta -\mu _kg\cos \theta [/tex]
Using 
Final velocity v=0
s=0.68 m
The answer is Dynamite.
Explosive, any substance or device that can be made to produce a volume of rapidly expanding gas in an extremely brief period. Chemical explosives are of two types; detonating, or high explosives and deflagrating, or low, explosives. Detonating explosives, such as TNT and dynamite, are characterized by extremely rapid decomposition and development of high pressure, whereas deflagrating explosives, such as black and smokeless powders, involve merely fast burning and produce relatively low pressures.
The student's claim did not follow the scientific method of discovery, hence, it is an opinion not a scientific claim.
<h3>What is the scientific method?</h3>
The scientific method is a procedure employed by scientific towards understanding the world around them as well giving explanation for phenomena in the natural world.
The scientific method involves:
- observations
- asking questions
- putting forward a hypothesis
- testing the hypothesis through experiments
- analyzing results of the experiments and drawing conclusions
- establishing a theory.
Since the student in question just put forward an opinion without testing it out using the scientific method, the statement is not a scientific claim.
Learn more about scientific method at: brainly.com/question/17216882
Answer:
ε = 2 V/cm
Explanation:
To calculate the mobility inside this bar, we just need to apply the expression that let us determine the mobility. This expression is the following:
ε = ΔV / L
Where:
ε: Hole mobility inside the bar
ΔV: voltage applied in the bar
L: Length of the bar
We already have the voltage and the length so replacing in the above expression we have:
ε = 2 V / 1 cm
<h2>
ε = 2 V/cm</h2><h2>
</h2>
The data of the speed can be used for further calculations, but in this part its not necessary.
Hope this helps
