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1 year ago

Gravitational force exist between you and the building why are you not pulled towards the building?

Physics

1 answer:

Nataly_w [17]1 year ago

3 0

Answer:

You are pulled towards that building. At the same time, that building is pulled towards you. Neither object creates enough gravitational force to really do anything. That is why you never notice any affect by either body, (you and a building).

Explanation:

You will surely get attracted towards the building.But it takes a lot of time depending on their masses.

This happens only when you are away from earth with that building.

Both of you will get attracted to it

if a third party with mass more than you or building is with you.

If it is on the earth.. Then the gravity between you and the building is negligible compared to the earth.Hence you will not get attracted towards the building in this case.

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The density of balsa wood is 0.170 g/cm3. What is the mass if the volume is 12.0 mL?

Harlamova29_29 [7]

Answer:

<h3>The answer is 2.04 g</h3>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

density = 0.17 g/cm³

1 mL = 1 cm³

12 mL = 12 cm³

So we have

mass = 0.17 × 12

We have the final answer as

Hope this helps you

8 0

2 years ago

A) A car accelerates uniformly at 3.7 m s⁻² as it passes a stationary road train. The initial speed of the car is 30 m s⁻¹, and

Tanya [424]

(a) The length of the train is 54.6 m

(b) The braking distance of the road train is 194.44 m

The given parameters:

acceleration of the car, a = 3.7 m/s²

initial velocity of the car, u = 30 m/s

final velocity of the car, v = 130 km/h = 36.11 m/s

To find:

the length of the train

The length of the train is the distance travelled by the car

The distance traveled by the car is calculated as:

$v^2 = u^2 + 2as\\\\2as = v^2 - u^2\\\\s = \frac{ v^2 - u^2}{2a} \\\\where;\\\\s \ is \ the \ distance \ travelled \ by \ the \ car\\\\s = \frac{(36.11)^2 - (30)^2}{2\times 3.7} \\\\s = 54.585 \ m\\\\s \approx 54.6 \ m$

Thus, the length of the train is 54.6 m

(b) The braking distance of a road train travelling at 25 m s⁻¹

$a = \frac{v_1^2}{2s_1} = \frac{v_2^2}{2s_2} \\\\Given;\\\\s_1 = 70 \ m\\\\v_1 = 15 \ m/s\\\\v_2 = 25 \ m/s\\\\s_2 = ?\\\\2s_2v_1^2 = 2s_1v_2^2\\\\s_2 = \frac{ 2s_1v_2^2}{2v_1^2} \\\\s_2 = \frac{s_1v_2^2}{v_1^2} \\\\s_2 = \frac{70\times 25^2}{15^2} \\\\s_2 = 194.44 \ m$

Thus, the braking distance of the road train is 194.44 m

Learn more here: brainly.com/question/19572178

6 0

1 year ago

A car has an initial velocity of 11.2 m /sec. the car accelerates at 10.0 m /s2 for 8.0 seconds. what is the velocity of the car

Vinil7 [7]

Initial velocity(u) = 11.2 m/s.
Final velocity(v) = ?
acceleration(a) = 10.2 m/s²

Using kinematic equation v = u + at

v = 11.2 + 10 x 8 = 11.2 + 80 = 91.2 m/s.

Therefore final velocity is 91.2 m/s.

7 0

2 years ago

Woman has a near point of 75.0 cm. What focal length, f, is necessary for the corrective lens so that he can hold his physics bo

Komok [63]

Answer:

The focal length of the lens must be 27.3cm

Explanation:

Image distance= -75 cm

Object distance= 20.0cm

From:

1/v + 1/u = 1/f

-1/75+ 1/20 = 1/f

11/300= 1/f

f= 300/11

f= 27.3cm

The focal length of the lens must be 27.3cm

8 0

2 years ago

Question 20 of 20

Sphinxa [80]

Answer:

Explanation:

hI I

6 0

1 year ago

Gravitational force exist between you and the building why are you not pulled towards the building?​

Gravitational force exist between you and the building why are you not pulled towards the building?