**Answer:**

How much energy does it take to melt a 16.87 g ice cube? ΔHfus = 6.02 kJ/mol How much energy does it take to melt a 16.87 g ice cube? = 6.02 kJ/mol

A. 108 kJ

B. 102 kJ

C. 5.64 kJ

D. 936 kJ

E. none of the above

**<em>5.64 kJ</em>**

**Explanation:**

The **Heat of fusion **is the heat energy required to **dissolve **a given mass of ice at **melting point**.

<h3>

**Step by Step Calculation**</h3>

The heat energy required to dissolve ice can be calculated using the expression below;

**Q = ΔH**** x m ...............................................1**

where Q is the heat energy required;

ΔH is the heat of fusion for ice;

m is the mole

All the parameters above are provided in the question except m, so to get m we use the molar mass of water (also for ice) which is 18.01528 g/mol
.

<em>This means that 18.01528 g of ice is contained in one mole, therefore the mole for 16.87 g of ice is given as;</em>

m = 0.9364 mole of ices

Now the parameters are complete, we are given;

ΔH = 6.02 kJ/mol

m = 0.9364 mol

Q =?

Substituting into equation 1, we have

Q = 6.02 kJ/mol x 0.9364 mol

**Q = 5.64 kJ**

<em>Therefore, the energy required to melt 16.87 g of ice is 5.64 kJ</em>

**Answer:**

latent heat, also called the heat of vaporization, is the amount of energy necessary to change a liquid to a vapour at constant temperature and pressure. The energy required to melt a solid to a liquid is called the heat of fusion, and the heat of sublimation is the energy

**Explanation:**

**Answer:**

The answer is: Pressure increases linearly with the depth

**Explanation:**

In this case, the definition of pressure is:

where F = mg is the weight of the fluid over the body, and A is the area of the surface to which the force is exerted. If we consider , then

.

Volume can be expressed as V = A*h, where A is the cross section of the column of the fluid over the body and h is the height of the column, in other words, the depth.

So

,

which means that pressure increases linearly with the depth in a factor of .

**Answer:**

Resistance, R = 8624.18 ohms

**Explanation:**

It is given that,

The emf of the circuit,

Capacitance of the capacitor,

Voltage across the capacitor, V = 10 V

**Time for which the wipers are to operate. The formula for the voltage across the voltage is given by :**

**So, the value of resistance used in the charging circuit is 8624.18 ohms. Hence, this is the required solution.**