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1 year ago

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Explain why convex mirrors can only produce virtual images. Please use at least 2 content related sentences. (ref: p.471-481)

1 answer:

34kurt1 year ago

8 0

Convex mirrors can only produce virtual images because the focal point and the center of curvature of the convex mirror are imaginary points and that cannot be reached.

<h3>What is virtual image?</h3>

This is referred to the opposite of a real image and cannot be obtained on a screen. It is formed from the apparent divergent of light rays from a point and not the actual one which is the major difference it has with a real image.

It is usually produced by a convex mirror because the focal point and the center of curvature of the convex mirror are imaginary points which can't be reached.

Read more about Convex mirrors here brainly.com/question/14269744

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A capacitor with an initial potential difference of 185 V is discharged through a resistor when a switch between them is closed

GrogVix [38]

Answer:

a. $\tau = 2.1161 s$

b. $V(18.8 \ s) = 0.0256 \ V$

Explanation:

<h3>a.</h3>

The equation for the voltage V of discharging capacitor in an RC circuit at time t is:

$V(t) = V_0 e^{(- \frac{t}{\tau}) }$

where $V_0$ is the initial voltage, and $\tau$ is the time constant.

For our problem, we know

$V_0 = 185 \ V$

and

$V(10 \ s) = V_0 e^{(- \frac{10 \ s}{\tau}) } = 1.64 \ V$

So

$185 \ V \ e^{(- \frac{10 \ s}{\tau}) } = 1.64 \ V$

$e^{(- \frac{10 \ s}{\tau}) } = \frac{1.64 \ V}{ 185 \ V }$

$ln (e^{(- \frac{10 \ s}{\tau}) } ) = ln (\frac{1.64 \ V}{ 185 \ V })$

$- \frac{10 \ s}{\tau} = ln (\frac{1.64 \ V}{ 185 \ V })$

$\tau = \frac{-10 \s}{ln (\frac{1.64 \ V}{ 185 \ V }) }$

This gives us

$\tau = 2.1161 s$

and this is the time constant.

<h3>b.</h3>

At t = 18.8 s we got:

$V(18.8 \ s) = 185 \ V \ e^{(- \frac{18.8 \ s}{2.1161 s}) }$

$V(18.8 \ s) = 185 \ V \ e^{(- \frac{18.8 \ s}{2.1161 s}) }$

$V(18.8 \ s) = 0.0256 \ V$

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In the inclined plane the objects that are thrown from a more inclined place go faster?

Mamont248 [21]

Assuming the objects roll down the inclined plane, yes.
If the object never touches the plane, then no.

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IRISSAK [1]

Answer:12.206 cm, $\theta =54.99^{\circ}$

Explanation:

Given

Insect walks 15 cm to the right

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Now it moves 10 cm up so its new position vector

$r_2=15i+10j$

Now it moves 8 cm left so its final position vector is

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$|r_3|=\sqrt{7^2+10^2}=\sqrt{149}=12.206 cm$

For direction, let \theta is the angle made by its position vector with x axis

$tan\theta =\frac{10}{7}=1.428$

$\theta =54.99^{\circ}$

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IgorC [24]

Answer:

a

Explanation:

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Complete question

The complete question is shown on the first and second uploaded image

Answer:∈

Answer to first question is shown on the second uploaded image.

Part B the Answer is:

The ratio $\frac{R}{a}$ is evaluated to be 49.99

Explanation:

The explanation is shown on the third ,fourth and fifth image.

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