To solve this problem it is necessary to apply the concepts related to the kinematic equations of linear motion. For this purpose, we will use the definition of the speed equivalent to the displacement made by a body in a fraction of time. From this definition we will relate the time and distance variables required in the problem
Here,
v = Velocity
d = Distance
t = Time
With our values we have,
The speed of light is the speed at which waves move, therefore using the same formula above, but to find the distance we would have
Here,
c = Speed velocity
We have then,
Therefore the distance between the Earth and the spaceship is
This is due to earths location in the solar system. Earth is in the habitat zone or the Goldie locks zone, in this zone it's not too hot or not too cold for water to exist. Other planets in different star systems have liquid oceans due to them being in the habitat zone.
Answer: P= mad/t or P=w/t so P= 300/6= 50 W
I believe the answer would be, refractor type telescopes because these are best used for planetary observations.
<span>Example Problems. Kinetic Energy (KE = ½ m v2). 1) The velocity of a car is 65 m/s and its mass is 2515 kg. What is its KE? 2) If a 30 kg child were running at a rate of 9.9 m/s, what is his KE? Practice Problems. IN THIS ORDER…. Page 2: #s 6, 7, 8, 5. Potential Energy. An object can store energy as the result of its position.</span><span>
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