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Tasya [4]
4 years ago
14

One reaction that produces hydrogen gas can be represented by the unbalanced chemical equation Mg+HCl=MgCl2+H2. What mass of HCl

is consumed by the reaction of 3.24 mol of Mg
Chemistry
1 answer:
Delicious77 [7]4 years ago
3 0
I the HCI is the mass of the equation but not always answer is Mg+HC H20
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Someone please help me before 1:00
DiKsa [7]

independent variable: how much bread there is

dependant variable: temperature, location, time, size.

hypothesis, the one with the bread will be way more moist than the one without.

control group: no bread at all.

experimental group: brownies with bread

constants: same tupperware, placement, time, size.

7 0
3 years ago
A ball slowing down as it rolls across a carpet is an example of what
vlada-n [284]

A ball slowing down as it rolls across a carpet is an example of friction.

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4 0
3 years ago
Read 2 more answers
Which molecule is usually comprised of six carbons in a ring (with six sides)?
Oksana_A [137]
The hydrocarbon is usually named using the prefix that would indicate or entail how many carbon are present in it. For six carbons, the name would begin with hexa-. For cyclic molecule, the name would begin further with cyclo-. Thus, for the molecule that is described above, the name would be, cyclohexane. 

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3 0
3 years ago
Oxidation number of Mg3N2
Fudgin [204]

Answer:

n=-3

Explanation:

Mg = +2  

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8 0
3 years ago
Seawater is typically 3.5% salt and has a density of 1.03 g/mL. How many grams of salt would be needed to prepare enough seawate
Bas_tet [7]

Answer:

Amount of salt needed is around 2.3*10³ g

Explanation:

The salt content in sea water = 3.5 %

This implies that there is 3.5 g salt in 100 g sea water

Density of seawater = 1.03 g/ml

Volume of seawater = volume of tank = 62.5 L = 62500 ml

Therefore, the amount of seawater required is:

=Density*Volume = 1.03g/ml*62500ml = 6.44*10^{4} g

The amount of salt needed for the calculated amount of seawater is:

=\frac{6.44*10^{4}g\ water*3.5g\ salt }{100g\ water} =2254 g =2.3*10^{3} g

8 0
3 years ago
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