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Determine the moles of oxygen gas (O2) needed to completely react with 1.975 moles of hydrogen gas (H2).

Pavlova-9 [17]

Answer:

0.9875 mole O₂

Explanation:

Rxn => H₂ + ¹/₂O₂ => H₂O

from above reaction, 1 mol H₂ requires ¹/₂ mol O₂ then 1.975 mol H₂ requires ¹/₂(1.975 mol)O₂ or 0.9875 mol O₂.

6 0

3 years ago

In a car crash, large accelerations of the head can lead to severe injuries or even death. A driver can probably survive an acce

Alexxandr [17]

Answer:

Velocity, u = 14.7 m/s

Explanation:

It is given that, a driver can probably survive an acceleration of 50 g that lasts for less than 30 ms, but in a crash with a 50 g acceleration lasting longer than 30 ms, a driver is unlikely to survive.

Let v is the highest speed that the car could have had such that the driver survived. Using a = -50 g and t = 30 ms

Using first equation of kinematics as :

$v=u+at$

In case of crash the final speed of the driver is, v = 0

$0=u+at$

$-u=at$

$-u=-50\times 9.8\times 30\times 10^{-3}$

u = 14.7 m/s

So, the highest speed that the car could have had such that the driver survived is 14.7 m/s. Hence, this is the required solution.

8 0

3 years ago

Ethylene (C2H4) is the starting material for the preparation of polyethylene. Although typically made during the processing of p

Solnce55 [7]

Answer:

1.17 grams

Explanation:

Let's consider the balanced equation for the combustion of ethylene.

C₂H₄(g) + 3 O₂(g) → 2 CO₂(g) + 2 H₂O(l)

We can establish the following relations:

1411 kJ are released (-1411 kJ) when 1 mole of C₂H₄ burns.
The molar mass of C₂H₄ is 28.05 g/mol.

The grams of C₂H₄ burned to give 59.0 kJ of heat (q = -59.0 kJ) is:

$-59.0kJ.\frac{1molC_{2}H_{4}}{-1411kJ} .\frac{28.05gC_{2}H_{4}}{1molC_{2}H_{4}} =1.17gC_{2}H_{4}$

8 0

3 years ago

Use molecular orbital theory to determine whether He2 2+ or He2 + is more stable. Use molecular orbital theory to determine whet

julia-pushkina [17]

Answer:

The He₂ 2+ ion is more stable since it has a higher bond order (bond order = 1) than the He₂ + ion (bond order = 1/2).

Explanation:

Molecular orbital of He₂⁺

$1\sigma_{1s}^21\sigma(star)_{1s}^1$

There are two electrons in bonding and 1 electron in antibonding orbital

Bond order = $\frac{(2-1)}{2}$

= $\frac{1}{2}$

Molecular orbital of He₂⁺²

$1\sigma_{1s}^21\sigma(star)_{1s}^0$

There are two electrons in bonding and 0 electron in antibonding orbital

Bond order = $\frac{(2-0)}{2}$

= 1

So bond order of He₂⁺² is 1 which is more stable than He₂⁺ whose bond order is $\frac{1}{2}$ .

7 0

3 years ago

9)

Molodets [167]

The correct answer is D

7 0

3 years ago

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