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Volgvan
3 years ago
9

Two blocks travel along a level frictionless surface. Block A is initially moving to the right, while block B is initially at re

st. The mass of block A is greater than the mass of block B. The positive x-direction is to the right. The magnitude of the change in momentum of block A is ______ the magnitude of the change in momentum of block B.
Physics
1 answer:
WARRIOR [948]3 years ago
4 0

Answer:

Explanation:

The magnitude of the change in momentum of block A is <u>equal and opposite </u>the magnitude of the change in momentum of block B.

According to law of conservation of momentum , there should not be any change in the  momentum in the system  .The system consists of A and B .  So if some change in momentum has occurred in A  , the other must have equal and opposite change in momentum so that they get cancel out and net change in momentum of system is zero.

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<h3>Explanation:</h3>

Given:

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1. Gravitational potential energy of a lifted person is equal to the work done.

PE_g=W=m\times g\times h\\Acceleration due to gravity = g = 9.8 \ m/s^2 \\PE_g= m = m\times g\times h= 70\times 9.8 \times 3 = 2058\ kg.m/s^2 = 2058\ J

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2. The Gravitational potential energy is converted into kinetic energy. Kinetic energy is being transferred to the person.

3. Kinetic energy gained = Potential energy lost = -PE_g = -2058\ kg.m/s^2

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4. Velocity = ?

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Solving for v, we get

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