Two blocks travel along a level frictionless surface. Block A is initially moving to the right, while block B is initially at re
1 answer:
You might be interested in
As per the question the distance of venus from sun is given as 0.723 AU
We have been asked to calculate the time period of the planet venus.
As per kepler's laws of planetary motion the square of time period of planet is directly proportional to the cube of semi major axis. mathematically
⇒ where is k is the proportionality constant
We may solve this problem by comparing with the time period of the earth . We know that time period of earth is 365.5 days
Hence
The distance of sun from earth is taken as 1 AU i.e the mean distance of earth from sun
Hence
The distance of venus from sun is 0.723 AU i.e
From keplers law we know that-
⇒
Putting the values mentioned above we get-
⇒
⇒
Hence the time period of venus is 224.388352752710 days
Please find attached photograph for your answer. Please do comment whether it is useful or not
