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3 years ago

The glowing of a neon light is caused by electrons emitting energy as they (1 point)

Physics

2 answers:

Pachacha [2.7K]3 years ago

6 0

The correct answer is:

The glowing of a neon light is caused by electrons emitting energy as they move from higher to lower energy levels.

Explanation:

Because each color is refracted conversely, each includes at a discrete angle, resulting in a fanning out and detachment of white light into the colors of the spectrum. Water droplets in the air can act in a practice similar to that of a prism, quitting the colors of sunlight to generate a spectrum accepted as a rainbow.

Lena [83]3 years ago

5 0

<span>The glowing of a neon light is caused by electrons emitting energy as they </span>move from higher to lower energy levels.

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lightning and thunder both occur at the same time why do you see the Lightning before you hear the thunder

denis23 [38]

Because the light from it travels to you about 874 thousand times
as fast as the sound does, so the hearing part falls behind the seeing
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5 0

2 years ago

Read 2 more answers

A straight wire of length 0.53 m carries a conventional current of 0.2 amperes. What is the magnitude of the magnetic field made

olga55 [171]

Explanation:

It is given that,

Length of wire, l = 0.53 m

Current, I = 0.2 A

(1.) Approximate formula:

We need to find the magnitude of the magnetic field made by the current at a location 2.0 cm from the wire, r = 2 cm = 0.02 m

The formula for magnetic field at some distance from the wire is given by :

$B=\dfrac{\mu_oI}{2\pi r}$

$B=\dfrac{4\pi \times 10^{-7}\times 0.2\ A}{2\pi \times 0.02\ m}$

B = 0.000002 T

$B=10^{-5}\ T$

(2) Exact formula:

$B=\dfrac{\mu_oI}{2\pi r}\dfrac{l}{\sqrt{l^2+4r^2} }$

$B=\dfrac{\mu_o\times 0.2\ A}{2\pi \times 0.02\ m}\times \dfrac{0.53\ m}{\sqrt{(0.53\ m)^2+4(0.02\ m)^2} }$

B = 0.00000199 T

B = 0.000002 T

Hence, this is the required solution.

4 0

3 years ago

sergij07 [2.7K]

Based on the nature of constructive interference,

none of the wave intersections will produce constructive interference.

<h3>What is constructive interference?</h3>

Constructive interference is interference that occurs when two waves of the same frequency amplitude and wavelength travelling in the same direction are superposed with the resultant effect of reinforcement of both waves to produce a larger wave.

Constructive interference occurs when the path difference between two identical waves at a point is:

delta s = n × wavelength

where n = 0, 1, 2, ...

For the various intersections:

1.77 cm crest intersecting with a 0.65 cm crest; n = 1.77/0.65 = 2.7
A 1.2 mm crest intersecting with a 3.9 mm trough is destructive.
A 4.55 N trough intersecting with a 1.59 N trough; n = 4.55/1.59 = 2.8
A 0.44 inch trough intersecting with a 0.72 inch crest is destructive.
A 7.42 mm trough intersecting with a 1.93 mm trough; n = 7.42/1.93 = 3.8

Therefore, none of the wave intersections will produce constructive interference

Learn more about constructive interference at: brainly.com/question/1040831

4 0

2 years ago

An unfortunate astronaut loses his grip during a spacewalk and finds himself floating away from the space station, carrying only

alexira [117]

Answer:

The answer is " $2.352 \ \frac{m}{s}$ "

Explanation:

$\to mass(m_1)=102 \ kg\\\\\to mass(m_2)=10 \ kg \\\\\to v=2.10\ \frac{m}{s}\\\\$

momentum before:

$\to p=(m_1+m_2)v$

$=(102+10)2.10\\\\=(102\times 2.10 +10 \times 2.10)\\\\=214.2+21\\\\=235.2$

momentum After:

$\to p=(m_1+m_2)v$

$=(102\times 0 +10 \times v)\\\\ =(0 +10v)\\\\=10v\\$

Calculating the conservation of momentum:

$\to \text{momentum before = momentum After}$

$\to 235.2=10v\\\\\to v= \frac{235.2}{10}\\\\ \to v=2.352 \ \frac{m}{s}$

3 0

2 years ago

A 2.17 g sample of acetylsalicylic acid required 23.88 mL of 0.5043 M NaOH for complete reaction. Addition of 13.46 mL of 0.4472

Paul [167]

Answer:

The pH of the mixture is 0.7926

Explanation:

Hi there!

The acetylsalicylic acid was completely neutralized by the sodium hydroxide so that the only protons present in the solution come from the HCl. The volume of the solution can be calculated as the addition of the volume of sodium hydroxide and the volume of HCl (assuming that the mixture is an ideal solution).

The number of moles of HCl added can be calculated as follows:

13.46 ml (0.4472 mol/1000 ml) = 6.019 × 10⁻³ mol

The volume of the solution is 13.46 ml + 23.88 ml = 37.34 ml

Then, we can calculate the concetration of protons in the solution:

[H] = 6.019 × 10⁻³ mol /0.03734 l = 0.1612 M

The pH of the mixture:

pH = -log[H]

pH = -log[0.1612] = 0.7926

4 0

2 years ago