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2 years ago

What must be true about the matter at the start of a fire versus the end?

Chemistry

1 answer:

quester [9]2 years ago

5 0

Explanation:

Three things are required in proper combination before ignition and combustion can take place---Heat, Oxygen and Fuel. There must be Fuel to burn. There must be Air to supply oxygen. There must be Heat (ignition temperature) to start and continue the combustion process.

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Number of SO2 molecules in 1.28 mol of SO2

dolphi86 [110]

Answer:

7.7056 x 10^23

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3 years ago

PLS HELP!!! ASAP

mina [271]

Answer: The answer is Fossil A is younger than the index fossil.

Explanation: Because it’s the newest layer

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3 years ago

an engineer wishes to design a container that will hold 12.0 mol of ethane at a pressure no greater than 5.00x10*2 kPa and a tem

OleMash [197]

Answer:

The minimum volume of the container is 0.0649 cubic meters, which is the same as 64.9 liters.

Explanation:

Assume that ethane behaves as an ideal gas under these conditions.

By the ideal gas law,

$P\cdot V = n\cdot R\cdot T$ ,

$\displaystyle V = \frac{n\cdot R\cdot T}{P}$ .

where

$P$ is the pressure of the gas,
$V$ is the volume of the gas,
$n$ is the number of moles of particles in this gas,
$R$ is the ideal gas constant, and
$T$ is the absolute temperature of the gas (in degrees Kelvins.)

The numerical value of $R$ will be $8.314$ if $P$ , $V$ , and $T$ are in SI units. Convert these values to SI units:

$P =\rm 5.00\times 10^{2}\;kPa = 5.00\times 10^{2}\times 10^{3}\; Pa = 5.00\times 10^{5}\; Pa$ ;
$V$ shall be in cubic meters, $\rm m^{3}$ ;
$T = \rm 52.0 \textdegree C = (52.0 + 273.15)\; K = 325.15\; K$ .

Apply the ideal gas law:

$\displaystyle \begin{aligned}V &= \frac{n\cdot R\cdot T}{P}\\ &= \frac{12.0\times 8.314\times 325.15}{5.00\times 10^{5}}\\ &= \rm 0.0649\; m^{3} \\ &= \rm (0.0649\times 10^{3})\; L \\ &=\rm 64.9\; L\end{aligned}$ .

4 0

3 years ago

A cube of plastic 1.2x10^-5 km on a side has a mass of 1.1 g. what is its density in g/cm^3

Vesna [10]

Length of 1 side 1.2*10^-5km =1.2*10^-5*10^5 =1.2cm

<span>volume of the cube (1.2)^3=1.728 cm^3 </span>

<span>density= mass/volume= 1.1/1.728=0.636 g/cm^3</span>

7 0

3 years ago

Read 2 more answers

Which of the following metals (M) will form an ionic compound with nitrogen with the general formula M3N2? Hint: Think about how

Basile [38]

Answer:

See explanation

Explanation:

The question is incomplete but i will try to give you all the necessary guide that you need in order to answer the question.

When compounds are formed, atoms exchange valency. The valency of nitrogen is three while that of the metal is two. The exchange yields M3N2.

If the compound has been specifically mentioned to be a metal, then it must be a group two element. It could be any of Mg, Ca, Sr, Ba or Ra. I did not mention Be here because most of its compounds are covalent.

This will help you to answer the complete question.

5 0

3 years ago

Read 2 more answers