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olasank [31]
2 years ago
8

Given the unbalanced equation:

Chemistry
1 answer:
Alenkasestr [34]2 years ago
4 0

When the equation is successfully balanced by utilizing the lowest whole integers, the coefficient of lithium, given the unbalanced equation _ li _ n2 --> _ li3n, is 6.

6Li + N2 2Li3N is a balanced chemical equation.

As a result, the lithium coefficient in the chemical equation is 6.

A balanced chemical equation is one in which the mass of the reactants and products are equal, and each element has an equal number of atoms on both sides of the equation.

In other words, the reaction's two opposing sides have the same mass and charge.

The law of conservation of mass states that the mass of the reactants and products of a chemical reaction should be equal.

Learn more about Balanced chemical equation here brainly.com/question/26694427

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What conversion factor would you use to find the number of moles in 3.52x10^24 molecules
solmaris [256]

Answer:

Conversion factor is 6.022 ×10^23 molecules/mole.

Number of moles is 5.845 moles

Explanation:

We are given;

3.52 × 10^24 molecules

Required to determine the conversion factor\

We know that according to the Avogadro's constant;

1 mole of a compound contains 6.022 ×10^23 particles

Therefore, 1 mole of a molecular compound contains  6.022 ×10^23 molecules.

Thus, the conversion factor in this case would be 6.022 ×10^23 molecules/mole.

Such that; 3.52 × 10^24 molecules  are equivalent to;

= 3.52 × 10^24 molecules ÷ 6.022 ×10^23 molecules/mole.

=5.845 moles

Thus, the conversion factor is 6.022 ×10^23 molecules/mole.

Number of moles is 5.845 moles

5 0
4 years ago
Convert 300g into kg​
leva [86]

Answer:

0.3kg

Explanation:

6 0
3 years ago
Calculate the % dissociation of 0.10 M solution of acetic acid (pKa = 4.75)
madreJ [45]

Given :

Molarity of acetic acid solution, M = 0.10 M.

pKa of acetic acid, pKa = 4.75 .

To Find :

Percentage dissociation of 0.10 M solution of acetic acid.

Solution :

We know, pK_a = -log\  K_a

Taking antilog both side, we get :

K_a = 1.78\times 10^{-5}

Since, acetic acid has 1 hydrogen atom to loose , so it is a monoprotic acid.

Now, percentage dissociation of monoprotic acid is given by :

\alpha = \sqrt{\dfrac{K_a}{C}}\\\\\alpha =\sqrt{ \dfrac{1.78\times 10^{-5}}{0.1}}\\\\\alpha =  0.0133\times 100 = 1.33 \%

Hence, this is the required solution.

3 0
3 years ago
The specific heat capacity of a certain type of cooking oil is 1.75 J/(g⋅∘C). What is the amount of heat exchanged when the temp
anygoal [31]

Answer:

Q = -811440 J

Explanation:

Given data:

Mass of oil = 2.76 Kg (2.76× 1000 = 2760 g)

Initial temperature = 191 °C

Final temperature = 23°C

Specific heat capacity of oil = 1.75 J/g.°C

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 23°C - 191 °C

ΔT = -168°C

Q = 2760 g ×1.75 J/g.°C  ×-168°C

Q = -811440 J

Negative sign show heat is released.

6 0
3 years ago
Which statements are true concerning our interpretation of the results of an experiment?
miskamm [114]

Answer:

3. Judgement may be affected by what we already think is true (prior knowledge).

Explanation:

This statement is the correct answer because someone could be bias. Due to biases, prior knowledge may be incorrect and our conclusion may be wrong if you don't focus on the data given.

7 0
3 years ago
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