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evablogger [386]
3 years ago
7

Name this compound please ​

Chemistry
1 answer:
jasenka [17]3 years ago
4 0

Answer:

Ethanol

Explanation:

2 C atoms and a single OH group.

Formula: C2H5OH

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How would you prepare 3.5 L of a 0.9M solution of KCl?
Fudgin [204]
Calculate the mass of the solute <span>in the solution :

Molar mass KCl = </span><span>74.55 g/mol

m = Molarity * molar mass * volume

m = 0.9 * 74.55 * 3.5

m = 234.8325 g 

</span><span>To prepare 0.9 M KCl solution, weigh 234.8325 g of salt in an analytical balance, dissolve in a beaker, shortly after transfer with the help of a funnel of transfer to a volumetric flask of 100 cm</span>³<span> and complete with water up to the mark, then cover the balloon and finally shake the solution to mix

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8 0
3 years ago
How many grams of KCl is needed to make .75 L of a 1 M solution of KCl?
Zielflug [23.3K]

Answer:

The answer to your question is 25.9 g of KCl

Explanation:

Data

Grams of KCl = ?

Volume = 0.75 l

Molarity = 1 M

Formula

Molarity = \frac{number of moles}{volume}

Solve for number of moles

Number of moles = Molarity x volume

Substitution

Number of moles = 1 x 0.75

Simplification

Number of moles = 0.75 moles

Molecular mass KCl = 39 + 35.5 = 34.5

Use proportions to find the grams of KCl

                          34.5 g of KCl ----------------  1 mol

                             x                  ----------------  0.75 moles

                            x = (0.75 x 34.5) / 1

                            x = 25.9 g of KCl

3 0
3 years ago
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