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svp [43]
3 years ago
13

Reaction intermediates differ from activated complexes in that A. they are stable molecules with normal bonds and are frequently

isolated. B. they are molecules with normal bonds rather than partial bonds and can occasionally be isolated. C. they are intermediate structures which have characteristics of both reactants and products. D. they are unstable and can never be isolated. E. all reactions involve reaction intermediates, but not all have activated complexes.
Chemistry
1 answer:
vova2212 [387]3 years ago
3 0

Answer:

they are molecules with normal bonds rather than partial bonds and can occasionally be isolated.

Explanation:

In chemistry, reaction intermediates are species that are formed from reactants and are subsequently being transformed into products as the reaction progresses. In other words,  reaction intermediates are species that do not appear in a balanced reaction equation but occur somewhere along the reaction mechanism of a non-elementary reaction. They are usually short lived species that possess a high amount of energy. They may or may not be isolated.

They are often molecular species with normal bonds unlike activated complexes that are sometimes hypervalent species.

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Answer:

Explanation:

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2 years ago
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ladessa [460]
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7 0
3 years ago
The kinetic energy of a 10.3 g golf ball traveling at 48.0 m/s is
Svetach [21]

To work out the kinetic energy of an object, you use the formula:


E = 0.5 x (mass) x (velocity)^2


One important thing, though. The units MUST be consistent. Mass needs to be in kilograms, and velocity in metres per second.


To convert the mass form grams to kilograms, we need to divide it by 1000, getting 0.0103 kg. Since the velocity is already in the units we need, we can just plug the numbers into the equation to get:


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3 0
3 years ago
At 524 mm Hg and 35 °C, a sample of gas occupies a volume of 275 ml. The gas is transferred to a 325-ml flask and the temperatur
Deffense [45]

Answer:

400.197mmHg

Explanation:

P1V1 / T1 = P2V2 / T2

Where P1=524 mm Hg V1 =275 ml T1 = 35°C +273 = 308k

V2= 325-ml T2= 5°C+273 = 278k , P2= ?

Substituting the values into the formula.

524 mm Hg ×275 ml /308k = P2×325-ml/278k

Cross multiply

524 mm Hg ×275 ml×278k=308k×P2×325-ml

40059800= 100100×P2

P2 = 40059800/100100

P2= 400.197mmHg

Hence, the second pressure will be 400.197mmHg

6 0
3 years ago
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