Answer:
x= 138.24 g
Explanation:
We use the avogradro's number
6.023 x 10^23 molecules -> 1 mol C2H8
26.02 x 10^23 molecules -> x
x= (26.02 x 10^23 molecules * 1 mol C2H8 )/6.023 x 10^23 molecules
x= 4.32 mol C2H8
1 mol C2H8 -> 32 g
4.32 mol C2H8 -> x
x= (4.32 mol C2H8 * 32 g)/ 1 mol C2H8
x= 138.24 g
Answer:
12 mi/h
Explanation:
Step 1: Given data
Step 2: Convert "d" to miles
We will use the conversion factor 1 mi = 1.60934 km.
6 km × 1 mi/1.60934 km = 3.7 mi
Step 3: Convert "t" to hours
We will use the conversion factor 1 h = 60 min.
19 min × 1 h/60 min = 0.32 h
Step 4: Calculate the average speed of the runner (s)
The speed is equal to the quotient between the total distance and the time elapsed.
s = d/t
s = 3.7 mi/0.32 h = 12 mi/h
Answer: I say it is A sorry if I'm incorrect
Explanation:
0.25 moles of CO2 is present in 11 grams of CO2.
Explanation:
A mole represents the number of chemical entities in an element or molecule.
Number of moles of an element or molecule is determined by the formula:
The Number of moles (n) = weight of the atom given ÷ atomic or molecular weight of the one mole of the element or molecule.
Themolar mass of one mole of carbon dioxide is:
12+ ( 16×2)
= 44 gram/mole
The given weight is 44 grams of carbon dioxide.
Putting the values in the equation,
n= 11 gms÷44 gms/ mole
n = 0.25 mole
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