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umka2103 [35]
3 years ago
8

Can you guys help me with this

Mathematics
2 answers:
nikdorinn [45]3 years ago
5 0

Answer:

11) 40

12)113

13) 105

11) 180-65-75

12) 180 - (180-62-51)

13) 360-100-60-95

Rzqust [24]3 years ago
3 0
1) all of them should add up to 180 so
65+75=140
180-140=40
F=40

2) finding x:
62+51=113
180-113= 67
X=67
We can know how much y equals from the two angles far away which we already calculated so y=113

C) all angles should add up to 360
100+95+60= 255
360-255=105
X=105

Hope this helps
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Please walk me through how to do this so I can di the other questions​
Naddik [55]

Answer:

Axis is a vertical line at x = 2

Vertex is (2, -1)

y-intercept is (0, 3)

Solutions are x = 1 and x = 3

Step-by-step explanation:

To draw the graph of the quadratic equation you must find at least 5 points lie on the graph by choose values of x and find their values of y

Let us do that

Use x = -1, 0, 1, 2, 3, 4, 5

∵ y = x² - 4x + 3

∵ x = -1

∴ y = (-1)² - 4(-1) + 3 = 1 + 4 + 3 = 8

→ Plot point (-1, 8)

∵ x = 0

∴ y = (0)² - 4(0) + 3 = 0 + 0 + 3 = 3

→ Plot point (0, 3)

∵ x = 1

∴ y = (1)² - 4(1) + 3 = 1 - 4 + 3 = 0

→ Plot point (1, 0)

∵ x = 2

∴ y = (2)² - 4(2) + 3 = 4 - 8 + 3 = -1

→ Plot point (2, -1)

∵ x = 3

∴ y = (3)² - 4(3) + 3 = 9 - 12 + 3 = 0

→ Plot point (3, 0)

∵ x = 4

∴ y = (4)² - 4(4) + 3 = 16 - 16 + 3 = 3

→ Plot point (4, 3)

∵ x = 5

∴ y = (5)² - 4(5) + 3 = 25 - 20 + 3 = 8

→ Plot point (5, 8)

→ Join all the points to form the parabola

From the graph

∵ The axis of symmetry is the vertical line passes through the vertex point

∵ x-coordinate of the vertex point is 2

∴ Axis is a vertical line at x = 2

∵ The coordinates of the vertex point of the parabola are (2, -1)

∴ Vertex is (2, -1)

∵ The parabola intersects the y-axis at point (0, 3)

∴ y-intercept is (0, 3)

∵ x² - 4x + 3 = 0

∵ The solutions of the equation are the values of x at y = 0

→ That means the intersection points of the parabola and the x-axis

∵ The parabola intersects the x-axis at points (1, 0) and (3, 0)

∴ Solutions are x = 1 and x = 3

3 0
3 years ago
Thrush us a landscape architect. For his first public project he is asked a small scale drawing of a garden to be placed in the
ehidna [41]

Answer:

Therefore, on the graph;

The height = 7.5 units

And base = 5.0 units

Attached is an image for further information;

Step-by-step explanation:

Given that;

1 unit on the grid represent 2m of the garden;

Ratio = 1/2 unit/m

For the height;

height h = 15m

On the graph;

h = 15m × 1/2 unit/m

h = 7.5 units

For the base;

Base b = 10m

On the graph;

b = 10m × 1/2 unit/m

b = 5 units

Therefore, on the graph;

The height = 7.5 units

And base = 5.0 units

6 0
3 years ago
Please help me......................................
Irina18 [472]

Answer:

148.5

Step-by-step explanation:

times all

3 0
3 years ago
A graduated cylinder is filled with 36pi cm^3 of liquid. The liquid is poured into a different cylinder that has a radius of 3 c
inysia [295]
Hope you got your answer.

5 0
3 years ago
Please help :) I have no clue & math isn’t my strong subject.
melisa1 [442]

Equation of a line that is perpendicular to given line is y=\frac{-7}{4} x+\frac{7}{4}.

Equation of a line that is parallel to given line is y=\frac{4}{7} x-\frac{69}{7}.

Solution:

Given line y=\frac{4}{7} x+4.

Slope of this line, m_1 = \frac{4}{7}

$\text{Slope of perpendicular line} = \frac{-1}{\text{Slope of the given line} }

                                   $m_2=\frac{-1}{m_1}

                                          $=\frac{-1}{\frac{4}{7} }

Slope of perpendicular line, m_2=\frac{-7}{4}

Passes through the point (–7, 5). Here x_1=-7, y_1=5.

Point-slope formula:

y-y_1=m(x-x_1)

$y-(-7)=\frac{-7}{4} (x-5)

$y+7=\frac{-7}{4} x+\frac{35}{4}

Subtract 7 from both sides, we get

$y=\frac{-7}{4} x+\frac{7}{4}

Equation of a line that is perpendicular to given line is y=\frac{-7}{4} x+\frac{7}{4}.

To find the parallel line:

Slopes of parallel lines are equal.

m_1=m_3

$m_3=\frac{4}{7}

Passes through the point (–7, 5). Here x_1=-7, y_1=5.

Point-slope formula:

$y-(-7)=\frac{4}{7} (x-5)

$y+7=\frac{4}{7} x-\frac{20}{7}

Subtract 7 from both sides,

$y=\frac{4}{7} x-\frac{69}{7}

Equation of a line that is parallel to given line is y=\frac{4}{7} x-\frac{69}{7}.

7 0
3 years ago
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