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umka2103 [35]
3 years ago
8

Can you guys help me with this

Mathematics
2 answers:
nikdorinn [45]3 years ago
5 0

Answer:

11) 40

12)113

13) 105

11) 180-65-75

12) 180 - (180-62-51)

13) 360-100-60-95

Rzqust [24]3 years ago
3 0
1) all of them should add up to 180 so
65+75=140
180-140=40
F=40

2) finding x:
62+51=113
180-113= 67
X=67
We can know how much y equals from the two angles far away which we already calculated so y=113

C) all angles should add up to 360
100+95+60= 255
360-255=105
X=105

Hope this helps
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4vir4ik [10]

Answer:

(a) The confidence interval is: 0.0304 ≤ π ≤ 0.0830.

(b) Upper confidence bound = 0.0787

Step-by-step explanation:

(a) The confidence interval for p (proportion) can be calculated as

p \pm z*\sigma_{p}

\sigma=\sqrt{\frac{\pi*(1-\pi)}{N} }\approx\sqrt{\frac{p(1-p)}{N} }

NOTE: π is the proportion ot the population, but it is unknown. It can be estimated as p.

p=17/300=0.0567\\\\\sigma=\sqrt{\frac{p(1-p)}{N} }=\sqrt{\frac{0.0567(1-0.0567)}{300} }=0.0134

For a 95% two-sided confidence interval, z=±1.96, so

\\LL = p-z*\sigma=0.0567 - (1.96)(0.0134) = 0.0304\\UL =p+z*\sigma= 0.0567 + (1.96)(0.0134) = 0.0830\\\\

The confidence interval is: 0.0304 ≤ π ≤ 0.0830.

(b) The confidence interval now has only an upper limit, so z is now 1.64.

UL =p+z*\sigma= 0.0567 + (1.64)(0.0134) = 0.0787

The confidence interval is: -∞ ≤ π ≤ 0.0787.

5 0
3 years ago
You buy 3.18 pounds of oranges, 1.25 pounds of peaches, and 1.96 pounds of grapes. What is your total bill
BabaBlast [244]

Answer:

$6.39

Step-by-step explanation:

Just add the cost of everything

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4 0
2 years ago
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A basketball player has made 6060​% of his foul shots during the season. Assume the shots are independent. ​
motikmotik

Answer:

a) 2.5 shots

b) 59.4 shots

c) 4.87 shots

Step-by-step explanation:

Probability of making the shot = 0.6

Probability of missing the shot = 0.4

a) The expected number of shots until the player misses is given by:

E(X) = \frac{1}{P(X)}=\frac{1}{0.4}  \\E(X) = 2.5\ shots

The expected number of shots until the first miss is 2.5

b) The expected number of shots made in 99 attempts is:

E=99*0.6\\E=59.4\ shots

He is expected to make 59.4 shots

c) Let "p" be the proportion shots that the player make, the standard deviation for n = 99 shots is:

s=\sqrt{n*p*(1-p)}\\ s= 4.87\ shots

The standard deviation is 4.87 shots.

7 0
3 years ago
A) There are 100 students who play at least one of volleyball, soccer and hockey, of these 50 play au three games, 84 play socce
Scilla [17]

Answer:

<h2>i) 3</h2><h2>ii) 5</h2>

Step-by-step explanation:

Let H be the set of students who play Hokey

     V be the set of students who play Volleyball

     S be the set of students who play Soccer

======================================

card(volleyball only) = card(V) - [card(V∩H∩S) + card(V∩H only) + card(V∩S only)]

                                 = 73 - [50 + (58-50) + (62-50)]

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                                 = 3

………………………………………………

Card(Hokey only) = 100 - [3 + 8 + 50 + 10 + 12 + 12]

                              = 100 - 95

                              = 5

…………………

<u><em>Note</em></u> :

A Venn diagram might be helpful in such case.

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