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Vilka [71]
3 years ago
12

What is the present Ba in Ba(NO3)2?​

Chemistry
1 answer:
Ira Lisetskai [31]3 years ago
3 0

Answer:

Percentage of Ba = 52.5%

Explanation:

We'll begin by calculating the molar mass of Ba(NO3)₂. This can be obtained as follow:

Molar mass of Ba(NO3)₂ = 137 + 2[14 +(16×3)]

= 137 + 2[14 + 48]

= 137 + 2[62]

= 137 + 124

= 261 g/mol

Next, we shall determine the mass of Ba in Ba(NO3)₂. This can be obtained as follow:

Mass of Ba in Ba(NO3)₂ = 137 g/mol

Finally, we shall determine the percentage of Ba in Ba(NO3)₂. This can be obtained as follow:

Percentage of Ba = mass of Ba / mass of Ba(NO3)₂ × 100

Percentage of Ba = 137 / 261 × 100

Percentage of Ba = 13700 / 261

Percentage of Ba = 52.5%

Thus, the percentage of Ba in Ba(NO3)₂ is 52.5%

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