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Law Incorporation [45]
2 years ago
7

In a mixture of 3 gases what is the total pressure of the gases if Gas A exerts a pressure

Chemistry
1 answer:
kirill [66]2 years ago
4 0

Answer:

760 mm of Hg

Explanation:

If the gases A , B and C are non reacting , then according to <u>Dalton's </u><u>Law </u><u>of</u><u> </u><u>Partial </u><u>Pressure</u> the total pressure exerted is equal to sum of individual partial pressure of the gases .

If there are n , number of gases then ,

P_{total}= P_1+P_2+P_3+\dots +P_n

Here ,

  • Partial pressure of Gas A = 400mm of Hg
  • Partial pressure of Gas B = 220 mm of Hg
  • Partial pressure of Gas C = 140mm of Hg

Hence the total pressure exerted is ,

P_{total}= P_{Gas\ A }+P_{Gas\ B }+P_{Gas\ C }

Substitute ,

P_{total}=( 400 + 220 + 140 )mm\ of \ Hg

Add ,

P_{total}= 760\ mm\ of \ Hg

<u>Hence</u><u> the</u><u> </u><u>total</u><u> pressure</u><u> exerted</u><u> by</u><u> the</u><u> </u><u>gases </u><u>is </u><u>7</u><u>6</u><u>0</u><u> </u><u>mm </u><u>of </u><u>Hg</u><u>.</u>

<em>I </em><em>hope</em><em> this</em><em> helps</em><em>.</em>

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8.43g of CaCl2·2H2O is dissolved in 40.0g of H2O. What is the molality of the solution? (Note that the H2O in the CaCl2·2H2O mus
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Answer:

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Explanation:

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B) THE DEPTH OF THE LAKE IS 0.060 m

Explanation:

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