All categories

2 years ago

In a mixture of 3 gases what is the total pressure of the gases if Gas A exerts a pressure

Chemistry

1 answer:

kirill [66]2 years ago

4 0

Answer:

760 mm of Hg

Explanation:

If the gases A , B and C are non reacting , then according to Dalton's Law of Partial Pressure the total pressure exerted is equal to sum of individual partial pressure of the gases .

If there are n , number of gases then ,

$P_{total}= P_1+P_2+P_3+\dots +P_n$

Here ,

Partial pressure of Gas A = 400mm of Hg
Partial pressure of Gas B = 220 mm of Hg
Partial pressure of Gas C = 140mm of Hg

Hence the total pressure exerted is ,

$P_{total}= P_{Gas\ A }+P_{Gas\ B }+P_{Gas\ C }$

Substitute ,

$P_{total}=( 400 + 220 + 140 )mm\ of \ Hg$

Add ,

$P_{total}= 760\ mm\ of \ Hg$

Hence the total pressure exerted by the gases is 760 mm of Hg.

I hope this helps.

You might be interested in

The variables _______ and ________ affect the gravitational force between objects.

anastassius [24]

I think the answer is A

5 0

4 years ago

Read 2 more answers

What kind of change occurs with no new substance being formed apex?

Andrew [12]

physical changes
Physical changes happen when something undergoes a transformation that does not alter their total inward arrangement. This appears differently in relation to the idea of compound change in which the creation of a substance changes or at least one substances consolidate or separate to frame a new one

5 0

3 years ago

What cause the ratio of PV/RT to drop below 1 when 1 mole of

pentagon [3]

Answer:

pressure and temperature are directly proportional.

Explanation:

At constant temperature and pressure the volume of a gas is directly proportional to the number of moles of gas. Also given a constant temperature and volume the pressure of a gas is directly proportional to the number of moles of gas.

This means that if V is constant then

P = n (RT/V) then n= PV/RT. As P is increased, T is also increased thereby decreasing the value of n since pressure and temperature are directly proportional.

6 0

3 years ago

In a titration of 0.35 M HCl and 0.35 M NaOH, how much NaOH should be added to 45.0 ml of HCl to completely neutralize the acid?

Bezzdna [24]

It would be the same amount. So, 45 ml of NaOH is required to be added to the 45 ml of HCI to neutralize the acid fully. Here is a brief calculation:

Firstly, here is your formula: M(HCI) x V(HCI) = M(NaOh) x V(NaOH)
With the values put in: 0.35 x 45 = 0.35 x V(NaOH)
= 45 ml.
There is 45 ml of V(NaOH)

Let me know if you need anything else. :)

- Dotz

6 0

3 years ago

Consider the following equilibrium reaction having gaseous reactants and products. 4HCl + O2 ⇌ 2H2O + Cl2 Which of the following

gulaghasi [49]

<h3>Answer;</h3>

B.The rate of forward reaction increases.

<h3>Explanation;</h3>

Le Chatelier's principle states that changing a factor such as concentration, temperature, or pressure of a reaction at equilibrium will cause the reaction to shift in the direction that counteracts the effect of that change.
Therefore, when reactants are added to a reaction at equilibrium shift when more reactants are added then the reaction shifts to the right to make more products.

3 0

4 years ago