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3 years ago

FREE 11 POINTSi will mark brainsit if i see crown

Mathematics

2 answers:

ehidna [41]3 years ago

6 0

Answer:

Thanks buckaroo

Step-by-step explanation:

Fofino [41]3 years ago

5 0

Answer:

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Which statement is true about the equation (x – 4)(x 2) = 16?

n200080 [17]

The roots of the given quadratic equation are 6 and -4.

The given quadratic equation is:

$(x-4)(x+2)=16$

<h3>What is a quadratic equation?</h3>

Any equation of the form $ax^{2} +bx+c=0$ is called a quadratic equation where $a\neq 0$ .

$x^{2} -2x-8=16$

$x^2-2x-24=0$

$x^{2} -6x+4x-24=0$

$x(x-6)+4(x-6)=0$

$(x-6)(x+4)=0$

$x=6$

$x=-4$

Hence, the roots of the given quadratic equation are 6 and -4.

To get more about quadratic equations visit:

brainly.com/question/1214333

3 0

2 years ago

What is the surface area of a cylinder with a radius of 6 cm and a height of 3 cm?

Hatshy [7]

Step-by-step explanation:

2πr^2h

2*22/7*6*6*3

2*22/7*36*3

2*22/7*108

5 0

3 years ago

WILL MARK BRAINLIEST ONLY HAVE 10 MINUTES

borishaifa [10]

Answer:

I think it is (2,2) but im not sure.

Step-by-step explanation:

6 0

3 years ago

What are the y and x intercepts of y=3(x-6)²-9 and y=-2(x+5)²+3 .. Thanks

JulsSmile [24]

1.
$y=3(x-6)^2-9 \\ \\
\hbox{x-intercept - y=0} \\
0=3(x-6)^2-9 \\
9=3(x-6)^2 \ \ \ |\div 3 \\
3=(x-6)^2 \\
\sqrt{3}=\sqrt{(x-6)^2} \\
\pm \sqrt{3}=x-6 \\
\pm \sqrt{3}+6=x \\
x=6+\sqrt{3} \ \lor \ x=6-\sqrt{3}} \\ \\
\hbox{y-intercept - x=0} \\
y=3(0-6)^2-9 \\
y=3 \times (-6)^2-9 \\
y=3 \times 36-9 \\
y=108-9 \\
y=99 \\ \\
\boxed{\hbox{x-intercepts: } 6+\sqrt{3} \hbox{ and } 6-\sqrt{3}} \\
\boxed{\hbox{y-intercept: } 99}$

2.
$y=-2(x+5)^2+3 \\ \\
\hbox{x-intercept - y=0} \\
0=-2(x+5)^2+3 \\
-3=-2(x+5)^2 \ \ \ |\div (-2) \\
\frac{3}{2}=(x+5)^2 \\
\sqrt{\frac{3}{2}}=\sqrt{(x+5)^2} \\
\pm \sqrt{\frac{3}{2}}=x+5 \\
\pm \sqrt{\frac{3}{2}}-5=x \\
x=\sqrt{\frac{3}{2}}-5 \ \lor \ x=-\sqrt{\frac{3}{2}}-5 \\ \\
\hbox{y-intercept - x=0} \\
y=-2(0+5)^2+3 \\
y=-2 \times 5^2 +3 \\
y=-2 \times 25+3 \\
y=-50+3 \\
y=-47 \\ \\ \boxed{\hbox{x-intercepts: } \sqrt{\frac{3}{2}}-5 \hbox{ and } -\sqrt{\frac{3}{2}}-5} \\ \boxed{\hbox{y-intercept: } -47}$

7 0

3 years ago

Triangle DEF has vertices D = (-4,-4), E = (-2,-4), and F = (-3,-1). 5! 3 2 1 -7 6 5 4 3 2 2 3 4 5 6 10 5 3. What is the area of

maxonik [38]

Answer:

$Area = 3$