Autoionization Reactions are those reactions in which ions or molecules ionizes spontaneously without adding any external reagent.
For Example,
Autoionization of water.
H₂O + H₂O ⇆ H₃O⁺ + OH⁻
Autoionization reaction of Methanol is shown below,
To plot the calibration curve, you need to prepare iron solutions with known concentrations and measure their absorbance. You need to pipet 0 mL of the diluted solution to have 0.00 mg of iron.
In spectrophotometry, to plot the calibration curve, you need to prepare solutions with known concentrations and measure their absorbance.
We have a standard iron solution with a concentration of 0.2500g/L of pure iron (C₁). We pipet 25.00mL (V₁) of this standard iron solution into a 500mL (V₂) volumetric flask and dilute up to the mark with distilled water.
We can calculate the concentration of the diluted solution (C₂) using the dilution rule.

Then, if we wanted to prepare the blank, that is, the solution that contains the same matrix but not the analyte, and whose concentration in iron is 0.00 mg/L, we wouldn't pipet any of the diluted solution.
To plot the calibration curve, you need to prepare iron solutions with known concentrations and measure their absorbance. You need to pipet 0 mL of the diluted solution to have 0.00 mg of iron.
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Enzymes affect the rate of the reaction in both the forward and reverse directions; the reaction proceeds faster because less energy is required for molecules to react when they collide. Thus, the rate constant (k) increases. Figure 3: Lowering the Activation Energy of a Reaction by a Catalyst.
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Answer:
- The percentage of unit cell volume that is occupied by atoms in a face- centered cubic lattice is 74.05%
- The percentage of unit cell volume that is occupied by atoms in a body-centered cubic lattice is 68.03%
- The percentage of unit cell volume that is occupied by atoms in a diamond lattice is 34.01%
Explanation:
The percentage of unit cell volume = Volume of atoms/Volume of unit cell
Volume of sphere = 
a) Percentage of unit cell volume occupied by atoms in face- centered cubic lattice:
let the side of each cube = a
Volume of unit cell = Volume of cube = a³
Radius of atoms = 
Volume of each atom =
= 
Number of atoms/unit cell = 4
Total volume of the atoms = 
The percentage of unit cell volume =
= 0.7405
= 0.7405 X 100% = 74.05%
b) Percentage of unit cell volume occupied by atoms in a body-centered cubic lattice
Radius of atoms = 
Volume of each atom =
=
Number of atoms/unit cell = 2
Total volume of the atoms = 
The percentage of unit cell volume =
= 0.6803
= 0.6803 X 100% = 68.03%
c) Percentage of unit cell volume occupied by atoms in a diamond lattice
Radius of atoms = 
Volume of each atom =
= 
Number of atoms/unit cell = 8
Total volume of the atoms = 
The percentage of unit cell volume =
= 0.3401
= 0.3401 X 100% = 34.01%
Answer:
approx 2.45g
Explanation:
2HCl + Na2SO4 → 2NaCl + H2SO4
2 : 1 : 2 : 1
0.05 0.025 (moles)
⇒ mH2SO4 = 0.025 × 98 = 2.45 g