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Readme [11.4K]
3 years ago
11

Which of the following statements about tolerance range is true?

Chemistry
1 answer:
vovikov84 [41]3 years ago
6 0
A. Tolerance range is different for different organisms.
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The aqueous hydroxide-promoted reaction of the compound with 2,2-dimethylpropanal (pivalaldehyde) at elevated temperature gives
ivolga24 [154]

Answer:

  The mechanism of this reaction i shown on the second uploaded image

The final product of the reaction is shown on the third uploaded image

The hydroxide would be first mixed with the ketone group before the aldehyde is added  

Explanation:

The compound given in the question is 2,2-dimethylpropanal (pivalaldehyde) the structural formula is shown on the first uploaded image

looking at the structurally formula we can see that the hydroxide promoted reaction of this compound would be between the ketone and aldehyde functional group present in this compound in the presence of a hydroxide

Now this process of the reaction is this

    The OH^- is first  made to react with the ketone group

     Then the aldehyde is added

     What happens is that that the OH^- would search for an acidic proton because it is a base and this acidic proton is present in ketone and absent in aldehyde group hence the reason for the first reaction with the ketone group before the aldehyde is added  

6 0
3 years ago
Use standard enthalpies of formation to calculate ΔH∘rxn for the following reaction______.2H2S(g)+3O2(g)→2H2O(l)+2SO2(g) ΔH∘rxn
Ahat [919]

Answer:

-1,103.39KJ/mol

Explanation:

We use the subtract the standard enthalphies of formation of the reactants from that of the products. It must be taken into consideration that the enthalpy of formation of elements and their molecules alone are not taken into consideration. Hence, what we would be considering are the standard enthalpies of formation of H2S, H2O and SO2.

In places where we have more than one mole, we multiply by the number of moles as seen in the balanced chemical equations.

The standard enthalpies of the molecules above are as follows:

H2S = -20.63KJ/mol

H2O = -285.8KJ/mol

SO2 = -296.84KJ/mol

O2 = 0KJ/mol

ΔrH⦵ = [2ΔfH⦵(H2O) + 2 ΔfH⦵(SO2)] − [ΔfH⦵(H2S) + 3

 ΔfH⦵(O2)]

ΔrH⦵ =[(2 × -285.8) + (2 × -296.84)]

-[ 3 × -20.63)]

= (-571.6 - 593.68 + 61.89) = -1,103.39KJ/mol

6 0
3 years ago
help, Look at the model below. Explain what is correct and/or incorrect about the model based on scale, proportion, and quantity
stiks02 [169]
One correct thging is that there are the same amount of positive and negative atoms
6 0
2 years ago
The boiling point of water is 1000C.
sergejj [24]

Answer:

a) The heat which we supply to water during boiling is used to overcome these forces of attraction between the particles so that they become totally free and change into a gas. This latent heat does not increase the kinetic energy of water particles and hence no rise in temperature takes place during the boiling of water.

b) Steam produces more severe burns than boiling water even though both are at 100oC because steam contains more heat, in the form of latent heat, than boiling water.

Explanation:

i hope this will help u

7 0
3 years ago
Which reason best explains why metals are shiny?
alexgriva [62]
Reflection, refracting, and the energy levels of molecular orbitals
8 0
3 years ago
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