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Mumz [18]
3 years ago
12

Be sure to answer all parts. Write a balanced equation (including physical states) for the following reaction: Sodium carbonate,

upon heating, produces sodium oxide and carbon dioxide.
Chemistry
1 answer:
aalyn [17]3 years ago
3 0

Answer:

I think it would be:

NaCO3 (s)-->Na2O (s) + CO2 (g)

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For the following pairs of ions, use the concept that a chemical compound must have a net charge of zero to predict the formula
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4 0
2 years ago
Which of the following happens when chlorine forms an ion?
Jlenok [28]

What  happens  when  chlorine  form  an ion  is that  it gains an electron and  has  an octet  in its  outer shell  ( answer  A)


<u><em> Explanation</em></u>

<u><em> </em></u>Chlorine is  is in atomic  number  17  in periodic table.

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chlorine therefore  has 7 valence electron therefore it  gain  1 electron  to form Cl- ( ion)

Cl- has  8  electron in its outer  shell (  it  obeys  octet  rule  of eight valence in outer shell.

7 0
3 years ago
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a 25.0-ml volume of a sodium hydroxide solution requires 19.6 ml of a 0.189 m hydrochloric acid for neutralization. a 10.0- ml v
Rashid [163]

<u>Concentration of NaOH = 0.148 molar, M</u>

<u>Concentration of H3PO4 = 0.172 molar, M</u>

<u></u>

Concentration x Volume  will give the number of moles of solute in that volume.  C*V = moles

Concentration  has a unit of (moles/liter).  When multiplied by the liters of solution used, the result is the number of moles.

Original HCl solution:  (0.189 moles/L)*(0.0196 L)= 0.00370 moles of HCl

The neutralization of 25.0 ml of sodium hydroxide, NaOH, requires 0.00370 moles of HCl.  The reaction is:

  NaOH + HCl > NaCl and H2O

This balanced equation tells us that neutralization of NaOH with HCl requires the same number of moles of each.  We just determined that the  moles of HCl used was 0.00370 moles.  Therefore, the 25.0 ml solution of NaOH had the same number of moles:  0.00370 moles NaOH.

The 0.00370 moles of NaOH was contained in 25.0 ml (0.025 liters).  The concentration of NaOH is therefore:  

    <u>(0.00370 moles of NaOH)/(0.025 L) = 0.148 moles/liter or Molar, M</u>

====

The phosphoric acid problem is handled the same way, but with an added twist.  Phosphoric acid is H3PO4.  We learn the 34.9 ml of the same NaOH solution (0.148M) is needed to neutralize the H3PO4.  But now the acid has three hydrogens that will react.  The balanced equation for this reaction is:

  H3PO4 + 3NaOH = Na3PO4 + 3H2O

Now we need <u><em>three times</em></u> the moles of NaOH to neutralize 1 mole of H3PO4.

The moles of NaOH that were used is:

  (0.148M)*(0.0349 liters) = 0.00517 moles of NaOH

Since the molar ratio of NaOH to H3PO4 is 3 for neutralization, the NaOH only neutralized (0.00517)*(1/3)moles of H3PO4 = 0.00172 moles of H3PO4.

The 0.00172 moles of H3PO4 was contained in 10.0 ml.  The concentration is therefore:

     (0.00172 moles H3PO4)/(0.010 liters H3PO4)

<u>Concentration of H3PO4 = 0.172 molar, M</u>

 

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9 months ago
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tensa zangetsu [6.8K]
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2 years ago
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The answer will be K, N, O.

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3 years ago
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