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Mumz [18]
3 years ago
12

Be sure to answer all parts. Write a balanced equation (including physical states) for the following reaction: Sodium carbonate,

upon heating, produces sodium oxide and carbon dioxide.
Chemistry
1 answer:
aalyn [17]3 years ago
3 0

Answer:

I think it would be:

NaCO3 (s)-->Na2O (s) + CO2 (g)

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7.895 g + 3.4 g round to the correct number significant figures
DIA [1.3K]

Answer:

11.3 g

Explanation:

7.895 + 3.4 = 11.295

When rounded to correct number of significant figures --> 11.3

There are 3 significant figures in 11.3

7 0
3 years ago
Describe polar covalent bonds using water as an example
Dahasolnce [82]
<span>A covalent bond is a bond formed by atom sharing.
In water molecule, there are twice the number of hydrogen atoms than the oxygen atoms. Its structure is H-O-H. The electronegative difference between the H and O allows them to be polar because on side there is positive charge and on another side there is negative charge.</span>
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3 years ago
How would you be able to tell if a train was moving?
lara [203]

Answer:

because I'm riding on it

8 0
3 years ago
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How might the government make sure scientific research is done in an ethical<br> way?
antiseptic1488 [7]

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They could possibly make daily check ups to the research facility?

7 0
3 years ago
What mass of lithium phosphate would you mass to make 2.5 liter of 1.06 M lithium
alex41 [277]

Answer:

Approximately 3.06 \times 10^{2}\; \rm g (approximately 306\; \rm g.)

Explanation:

Calculate the quantity n of lithium phosphate in V = 2.5\; \rm L of thisc = 1.06\; \rm M = 1.06\; \rm mol \cdot L^{-1} lithium phosphate solution.

\begin{aligned}n &= c \cdot V\\ &= 2.5\; \rm L \times 1.06\; mol \cdot L^{-1}\\ &= 2.65\; \rm mol\end{aligned}.

Empirical formula of lithium phosphate: \rm Li_3PO_4.

Look up the relative atomic mass of \rm Li, \rm P,and \rm O on a modern periodic table:

  • \rm Li: 6.94.
  • \rm P: 30.974.
  • \rm O: 15.999.

Calculate the formula mass of \rm Li_3PO_4:

M(\rm Li_3PO_4) = 3 \times 6.94 + 30.974 + 4 \times 15.999 = 115.79\; \rm g \cdot mol^{-1}.

Calculate the mass of that n = 2.65\; \rm mol of \rm Li_3PO_4 formula units:

\begin{aligned}m &= n \cdot M \\ &= 2.65\; \rm mol \times 115.79\; \rm g\cdot mol^{-1} \\ &\approx 3.06 \times 10^{2}\; \rm g \end{aligned}.

5 0
3 years ago
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