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Natalija [7]
2 years ago
9

A 200 g mass is placed on the meter stick 20 cm from the fulcrum. An

Physics
1 answer:
stira [4]2 years ago
3 0

Answer:

m = 500 grams

Explanation:

Assuming that the fulcrum is at the midpoint of a uniform meter stick, the moments about the fulcrum must be equal and opposite.

the 200 g mass makes a moment

200(g)[20] = 4000g gm•cm

the other mass must also create a moment of the same value

m(g)[8] = 4000g

m[8] = 4000

m = 500 grams

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hoa [83]

Answer:

Stress = 4.67 * 10^-7 N/m²

Explanation:

Young's modulus of the material = Stress/Strain

Given

Young's modulus  = 228 x 10^9 Pa

Stress =  106,483 Pa

Required

Strain

From the formula;

Strain = Stress/Young modulus

Strain =  106,483 /228 x 10^9

Stress = 4.67 * 10^-7 N/m²

3 0
3 years ago
A horizontal line on a displacement-time graph means the object is
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Answer:

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4 0
3 years ago
1. A ball with a mass of 2.3 kg travels with a velocity of 10 m/s. What is it's kinetic energy?
monitta

Answer:

KE=½mv²

KE=½2.3kg×(10m/s)²

KE=½2.3kg×100m²/s²

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2 years ago
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aivan3 [116]

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3 years ago
In a wire, when elongation is 4 cm energy stored is E. if it is stretched by 4 cm, then what amount of elastic potential energy
myrzilka [38]
<h2>Answer:</h2>

4E

<h2>Explanation:</h2>

The elastic potential energy of an elastic material (e.g a spring, a wire), is the energy stored when the material is stretched or compressed. It is given by

U = \frac{1}{2}kx^2               --------------------(i)

Where;

U = potential energy stored

k = spring constant of the material

x = elongation (extension or compression of the material).

<em>From the first statement;</em>

<em>when elongation (x) is 4cm, energy stored (U) is E</em>

<em>Substitute these values into equation (i) as follows;</em>

E = \frac{1}{2}k(4)^2

E = 8k

<em>Make k subject of the formula</em>    

k = \frac{E}{8}   [measured in J/cm]

<em>From the second statement;</em>

<em>It is stretched by 4cm.</em>

This means that total elongation will be 4cm + 4cm = 8cm.

The potential energy stored will be found by substituting the value of x = 8cm and k = \frac{E}{8} into equation (i) as follows;

U = \frac{1}{2}\frac{E}{8} (8)^2  

U = \frac{1}{2}{8E}

U = {4E}

Therefore, the potential energy stored will now be 4 times the original one.

3 0
3 years ago
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