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3 years ago

9

A 200 g mass is placed on the meter stick 20 cm from the fulcrum. An

1 answer:

stira [4]3 years ago

3 0

Answer:

m = 500 grams

Explanation:

Assuming that the fulcrum is at the midpoint of a uniform meter stick, the moments about the fulcrum must be equal and opposite.

the 200 g mass makes a moment

200(g)[20] = 4000g gm•cm

the other mass must also create a moment of the same value

m(g)[8] = 4000g

m[8] = 4000

m = 500 grams

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I believe the correct response would be B. It would decrease.

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How much pressure is applied to the ground

statuscvo [17]

Answer:

Pressure applied by the man= 285103.125 $Pa$ or 41.35 $lb/in^{2}$

Explanation:

Pressure is defined as the perpendicular force applied per unit area.

i.e. $Pressure=\frac{Force}{Area}$

Now, $Force= mg$

where, $m$ = mass of the body(man) = 93 kg

$g$ = acceleration due to gravity of Earth = 9.81 $m/{s^{2}}$

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therefore $Area=2(0.04)^{2}$ $m^{2}$

and putting in the values, we get,

$Pressure=\frac{93\times9.81}{2\times(0.04)^{2}}Nm^{-2}=285103.125Nm^{-2}$

Now we need to convert to our required units:

$1Nm^{-2}=1Pa\\1Pa=0.000145038lb/in^{2}$

(We can get the above result by individually converting kg to lb and meters to inches respectively)

Using the above relations we get,

$Pressure=285103.125Pa=0.000145038\times285103.125lb/in^{2}=41.35lb/in^{2}$

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3 years ago

What is the power of a circuit with voltage 12 V and current 8.0<br> A?

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3 years ago

If the humidity in a room of volume 410 m3 at 25 ∘C is 70%, what mass of water can still evaporate from an open pan? Express you

Keith_Richards [23]

Answer:

$m=1864.68\ g$

Explanation:

Given:

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temperature of the room, $T=25+273=298\ K$

<u>Saturation water vapor pressure at any temperature T K is given as:</u>

<u /> $p_{sw}=\frac{e^{(77.3450 + 0.0057\times T - \frac{ 7235}{T} )}}{T^{8.2}}$ <u />

putting T=298 K we have

$p_{sw}=3130\ Pa$

<u>The no. of moles of water molecules that this volume of air can hold is:</u>

Using Ideal gas law,

$P.V=n.R.T$

$n=\frac{P_{sw}.V}{R.T}$

$n=\frac{3130\times 410}{8.314\times 298}$

$n=518\ moles$ is the maximum capacity of the given volume of air to hold the moisture.

Currently we have 80% of n, so the mass of 20% of n:

$m=(20\%\ of\ n)\times M}$

where;

M= molecular mass of water

$m=0.2\times 518\times 18$

$m=1864.68\ g$ is the mass of water that can vaporize further.

3 0

3 years ago