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Irina18 [472]
2 years ago
15

Write the equation in standard form. x = -4y + 8 *

Mathematics
1 answer:
Vsevolod [243]2 years ago
8 0

Answer:

x+4y=8

Step-by-step explanation:

graph shown below

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322.788 is the answer to your ?
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What are the solutions to the equation <br><img src="https://tex.z-dn.net/?f=2%20%7Cx%20-%202%7C%20%20-%208%20%3D%2020" id="TexF
leva [86]

The solutions of the equation are -12 and 16

Step-by-step explanation:

Absolute value describes the distance of a number on the number line from 0 without considering which direction from zero the number lies. The absolute value of a number is never negative, if IxI = a, where a > 0, then

  • x = a
  • x = -a

∵ 2Ix - 2I - 8 = 20

- At first add 8 to both sides

∴ 2Ix - 2I = 28

- Then divide both sides by 2

∴ Ix - 2I = 14

Now By using the notes above equate x - 2 by 14 and -14

∵ x - 2 = 14

- Add 2 to both sides

∴ x = 16

∵ x - 2 = -14

- Add 2 to both sides

∴ x = -12

The solutions of the equation are -12 and 16

Learn more:

You can learn more about solving equations in brainly.com/question/2386054

#LearnwithBrainly

4 0
3 years ago
Which is the following number has a prime factorization of 2 x 5x5? 50. 20. 30. 15.​
dybincka [34]
AnsweR = 50
Explanation = 50
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I need help ASAP 30 points+brainleist
yulyashka [42]

Answer:

A) 40 feet.

B) 7 inches.

Step-by-step explanation:

A) To acquire 8 inches, multiply the corresponding scale factor by 8:

1 inch equals 5 feet; 8 inches equals 40 feet

The genuine house stands 40 feet tall.

B) You can write the percentage if you want...

dwg / (35 feet) = 1 in / (5 ft)

When you multiply by 35 feet, you get...

7 in dwg = (1 in)(35 ft)/(5 ft)

In the scale drawing, the home measures <em>7 inches in length</em>.

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Need help with Calculus 1 inverse trig functions
lidiya [134]

Answer:

\displaystyle y'=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{2+2x^2+2x\sqrt{1+x^2}}

Step-by-step explanation:

<u>The Derivative of a Function</u>

The derivative of f, also known as the instantaneous rate of change, or the slope of the tangent line to the graph of f, can be computed by the definition formula

\displaystyle f'(x)=\lim\limits_{\Delta x \rightarrow 0}\frac{f(x+\Delta x)-f(x)}{\Delta x}

There are tables where the derivative of all known functions are provided for an easy calculation of specific functions.

The derivative of the inverse tangent is given as

\displaystyle (tan^{-1}u)'=\frac{u'}{1+u^2}

Where u is a function of x as provided:

y=3tan^{-1}(x+\sqrt{1+x^2})

If we set

u=(x+\sqrt{1+x^2})

Then

\displaystyle u'=1+\frac{2x}{2\sqrt{1+x^2}}

\displaystyle u'=1+\frac{x}{\sqrt{1+x^2}}

Taking the derivative of y

y'=3[tan^{-1}(x+\sqrt{1+x^2})]'

Using the change of variables

\displaystyle y'=3[tan^{-1}u]'=3\frac{u'}{1+u^2}

\displaystyle y'=3\frac{u'}{1+u^2}=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{1+(x+\sqrt{1+x^2})^2}

Operating

\displaystyle y'=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{1+x^2+2x\sqrt{1+x^2}+1+x^2}

\boxed{\displaystyle y'=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{2+2x^2+2x\sqrt{1+x^2}}}

8 0
3 years ago
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