Ask question

Ask question

All categories

2 years ago

11

Which of the following digits could replace the in the ten thousands place to make this statement true? 706,103 rounds to 800,00

0 if we round to the nearest hundred thousand, Choose all answers that apply (A ) 3 В 5 7 8
4th grade

1 answer:

Travka [436]2 years ago

7 0

Answer:

numbers <u>5-9</u> could replace the ten thousand place to make the statement true.

<u>5, 7, 8</u>

Step-by-step explanation:

Have a nice day!

You might be interested in

Find an equation of the sphere containing all surface points P = (x, y, z) such that the distance from P to A(−3, 6, 3) is "twic

Marina86 [1]

Answer:

Equation of Sphere = $x^{2}$ + $y^{2}$ + $z^{2}$ - 18x - 4/3y +10z + 142/3 = 0

Step-by-step explanation:

Data Given:

P = (x,y,z)

Distance from P to A (-3,6,3) = Twice the distance from P to B(6,2,-3)

Solution:

Find the equation of the sphere:

It is given that:

PA = 2PB

Squaring both sides:

$(PA)^{2} = (2PB)^{2}$

$(PA)^{2} = 4 (PB)^{2}$

$(x - (-3))^{2}$ + $(y - 6)^{2}$ + $(z-3)^{2}$ = 4 x $(x-6)^{2}$ + $(y-2)^{2}$ + $(z-(-3))^{2}$

Solving the above equation:

$(x + 3))^{2}$ + $(y - 6)^{2}$ + $(z-3)^{2}$ = 4 x { $(x-6)^{2}$ + $(y-2)^{2}$ + $(z + 3))^{2}$ }

$x^{2}$ + 9 + 6x + $y^{2}$ + 36 - 12y + $z^{2}$ + 9 - 6z = 4 { $x^{2}$ + 36 - 12x + $y^{2}$ + 4 - 4y + $z^{2}$ + 9 + 6z}

$x^{2}$ + 9 + 6x + $y^{2}$ + 36 - 12y + $z^{2}$ + 9 - 6z = 4 $x^{2}$ + 144 - 48x +4 $y^{2}$ + 16 - 16y + 4 $z^{2}$ + 36 + 24z

Putting the right hand side = 0 and solving the equation:

$x^{2}$ - 4 $x^{2}$ + $y^{2}$ - 4 $y^{2}$ + $z^{2}$ - 4 $z^{2}$ + 6x + 48x - 12y +16y -6z - 24z + 9 + 36 + 9 -144 - 16 - 36 = 0

-3 $x^{2}$ - 3 $y^{2}$ -3 $z^{2}$ + 54x + 4y -30z -142 = 0

Taking (-) common

- ( 3 $x^{2}$ + 3 $y^{2}$ + 3 $z^{2}$ - 54x - 4y +30z + 142) = 0

3 $x^{2}$ + 3 $y^{2}$ + 3 $z^{2}$ - 54x - 4y +30z + 142 = 0

dividing the whole equation by 3

$x^{2}$ + $y^{2}$ + $z^{2}$ - 54/3x - 4/3y +30/3z + 142/3 = 0

$x^{2}$ + $y^{2}$ + $z^{2}$ - 54/3x - 4/3y +30/3z + 142/3 = 0

$x^{2}$ + $y^{2}$ + $z^{2}$ - 18x - 4/3y +10z + 142/3 = 0

7 0

3 years ago

. Look at each equation and possible solution. Is the solution correct? Select Yes or No for

insens350 [35]

A. No B. No C. Yes I honestly don’t know if that’s 100% right tho

4 0

3 years ago

Find three different complex fractions that simplafy to 1/4

Nostrana [21]

The answer is 3 1/4 if I'm correct

5 0

2 years ago

HEY! GOT A BUTT LOAD OF HW DUE TOMORROW PLS HELP BRAINLIEST ANSWER INCLUDED! Solve. How much pure acid is in 520 milliliters of

Rama09 [41]

540ml with 12% solution

get 12% of 540

540 times 0.12 = 64.8 ml of pure acid

3 0

3 years ago

An airplane flies from City 1 at (0, 0) to City 2 at (33, 56) and then to City 3 at (23, 32). What is the total number of miles

uranmaximum [27]

Answer:

The airplane flies 95 miles.

Step-by-step explanation:

First we need to find the distance for the first segment using the formula for distance $D=\sqrt{(x_{2}-x_{1})^2 + (y_{2}-y_{1})^2}$ . Let's say $(x_{1},y_{1})$ is (0, 0) and $(x_{2},y_{2})$ is (33, 56). This gets us that the length of this segment is 65 miles.
Next, we need to find the distance for the second segment. Using the same formula for distance $D=\sqrt{(x_{2}-x_{1})^2 + (y_{2}-y_{1})^2}$ , we can say $(x_{1},y_{1})$ is now (33, 56) and $(x_{2},y_{2})$ is now (23, 32). This gets us that the length of this segment is 26 miles.
To get the total distance traveled, add the length of these two segments together (65 miles + 26 miles) to get 91 total miles traveled.

7 0

2 years ago

Read 2 more answers