Y = -2/3x + 5....the slope here is -2/3. A perpendicular line will have a negative reciprocal slope. To find the negative reciprocal, we flip the slope and change the sign. So our perpendicular line will have a slope of 3/2 (see how I flipped -2/3 making it -3/2....and then changed the sign, making it 3/2)
y = mx + b
slope(m) = 3/2
(8,1)....x = 8 and y = 1
now we sub and find b, the y int
1 = 3/2(8) + b
1 = 12 + b
1 - 12 = b
-11 = b
so ur perpendicular equation is : y = 3/2x - 11 <==
Answer:
(-3,-11)
Step-by-step explanation:
Compare the given quadratic equation with the general quadratic equation.
a=1, b=6 and c=-2
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Subsitute
for
in given quadratic equation.
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The minimum point is (-3,-11).
Answer:
80 tickets
Step-by-step explanation:
Given the profit, y, modeled by the equation, y = x^2 – 40x – 3,200, where x is the number of tickets sold, we are to find the total number of tickets, x, that need to be sold for the drama club to break even. To do that we will simply substitute y = 0 into the given the equation and calculate the value of x;
y = x^2 – 40x – 3,200,
0 = x^2 – 40x – 3,200,
x^2 – 40x – 3,200 = 0
x^2 – 80x + 40x – 3,200 = 0
x(x-80)+40(x-80) = 0
(x+40)(x-80) = 0
x = -40 and x = 80
x cannot be negative
Hence the total number of tickets, x, that need to be sold for the drama club to break even is 80 tickets
I guess it’s A not sure tho