The <u>different</u> selections of<u> one</u> meat and <u>one</u> vegetable are possible are 18 selections.
Since the Hickory Stick has a selection of 3 meats and 6 vegetables, the number of ways we can select <u>one </u>meat out of 3 is ³C₁ = 3.
Also, the number of ways we can select <u>one </u>vegetable out of 6 is ⁶C₁ = 6.
So, the total number of selections of <u>one</u> meat and <u>one</u> vegetable is ³C₁ × ⁶C₁ = 3 × 6
= 18 selections
So, the <u>different</u> selections of<u> one</u> meat and <u>one</u> vegetable are possible are 18 selections.
Learn more about combination here:
brainly.com/question/19341024
To find the number or rows, divide the total number of students by the number in each row.
63 / 7 = 9 rows.
Answer:
x = 46
Step-by-step explanation:
Given 2 secants from an external point to the circle, then
The product of the external part and the whole of one secant is equal to the product of the external part and the whole of the other secant, that is
2(2 + x) = 6(6 + 10)
2(2 + x) = 6 × 16 = 96 ( divide both sides by 2 )
2 + x = 48 ( subtract 2 from both sides )
x = 46
the answer would be -8<x<2
