<span>One mol of NaCl (6.02 x1023 formulas) has a mass of 58.44 g. Concept 2. The relation between molecular (formula) mass and molar mass. To obtain one mole of copper atoms (6.02 x 1023 atoms), weigh out 63.55 g copper.</span>

6 0

3 years ago

Please answer this I need it answered really soon thank you so much whoever answers this and I will give BRAINLIEST!!

max2010maxim [7]

Answer:

B extinction

Explanation:

as the species does not exist any more, the species is extinct, therefore making the pictured fossil of an extinct species

hope this helps

3 0

3 years ago

Read 2 more answers

At 170C, a sample of hydrogen gas occupies 125cm3. What will be the volume at 1000C? =161cm3 If the volume of a given mass of ga

pickupchik [31]

1. V= 161

2. V = 37.3

<h3 /><h3>Further explanation </h3>

Charles's Law states that

<em>When the gas pressure is kept constant, the gas volume is proportional to the temperature </em>

$\tt \dfrac{V1}{T1}=\dfrac{V2}{T2}$

$\tt \dfrac{125}{17+273.15~K}=\dfrac{V2}{100+273.15}\\\\V2=160.7\rightarrow 161~cm^3$

$\tt \dfrac{27.3}{0+273.15`K}=\dfrac{V2}{100+273.15}\\\\V2=37.3~cm^3$

3 0

3 years ago

In calculating the concentration of [Cu(NH3)4]2+ from [Cu(H2O)4]2+, the stepwise formation constants are as follows: K1=1.90×104

pashok25 [27]

Answer:

Kf = 1.11x10¹³

Explanation:

The value of Kf for a multistep process that involves an equilibrium at each step, is the multiplication of the constant of the equilibrium of each step.

Kf = K1xK2xK3xK4

Kf = 1.90x10⁴ x 3.90x10³ x 1.00x10³ x 1.50x10²

Kf = 1.11x10¹³

4 0

3 years ago