A substance that has no specific volume changes to a substance that has a specific volume.
To solve this question you need to calculate the number of the gas molecule. The calculation would be:
PV=nRT
n=PV/RT
n= 1 atm * 40 L/ (0.082 L atm mol-1K-<span>1 * 298.15K)
</span>n= 1.636 moles
The volume at bottom of the lake would be:
PV=nRT
V= nRT/P
V= (1.636 mol * 277.15K* 0.082 L atm mol-1K-1 )/ 11 atm= <span>3.38 L</span>
Answer:
0.0177 L of nitrogen will be produced
Explanation:
The decomposition reaction of sodium azide will be:
As per the balanced equation two moles of sodium azide will give three moles of nitrogen gas
The molecular weight of sodium azide = 65 g/mol
The mass of sodium azide used = 100 g
The moles of sodium azide used = 
so 1.54 moles of sodium azide will give = 
mol
the volume will be calculated using ideal gas equation
PV=nRT
Where
P = Pressure = 1.00 atm
V = ?
n = moles = 2.31 mol
R = 0.0821 L atm / mol K
T = 25 °C = 298.15 K
Volume = 
Answer is: the hydrogen ion concentration is 10⁻¹⁰ mol/L, solution is basic.
[OH⁻] =0.00001 mol/L = 10⁻⁴ M.
[OH⁻]·[H⁺<span>] = Kw.
</span>0.00001 mol/L ·[H⁺] = 10⁻¹⁴ mol²/L².
[H⁺] = 10⁻¹⁴ mol²/L²÷ 10⁻⁴ mol/L.
[H⁺] = 10⁻¹⁰ mol/L.
pH = -log[H⁺].
pH = -log(10⁻¹⁰ mol/L).
pH = 10.
If pH is less than seven, solution is acidic; greater than seven, solution is basic; equal seven, solution is neutral.
