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nadezda [96]
4 years ago
7

PLEASE HELP ME NOW I NEED HELP What will happen if a single crystal is introduced into a super-saturated solution? a. The crysta

l will dissolve c. The solute will begin to form crystals b. Nothing d. The solution will vaporize Please select the best answer from the choices provided A B C D
Chemistry
1 answer:
Klio2033 [76]4 years ago
4 0

Answer:

c

It excess out the crystal

You might be interested in
From this list, select the element that forms π bonds most readily. from this list, select the element that forms bonds most rea
Finger [1]

Nonmetals which are located in the second row form pi bonds more easily than the elements situated in the third row and below. Actually there are no compounds or molecules known that forms covalent bonds to the noble gas Ne and Ar. Hence the other second row element which is Carbon, is the element that forms pi bonds most readily.

 

Answer:

<span>C</span>

3 0
3 years ago
Use the standard reaction enthalpies given below to determine ΔH°rxn for the following reaction: P4(g) + 10 Cl2(g) → 4PCl5(s) ΔH
Pie

Answer: -1835 kJ

Explanation:

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to Hess’s law, the chemical equation can be treated as algebraic expressions and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

PCl_5(s)\rightarrow PCl_3(g)+Cl_2(g)  \Delta H_1=+157kJ (1)

P_4(g)+6Cl_2\rightarrow 4PCl_3(g)  \Delta H_2=-1207J (2)

Net chemical equation:

P_4(g)+10Cl_2(g)\rightarrow 4PCl_5(s)  \Delta H=? (3)

Multiplying equation (1) by 4,  and reversing we get

4PCl_3(g)+4Cl_2(g)\rightarrow 4PCl_5(s)  \Delta H_4=4\times -157kJ=-628kJ (4)

Adding (2) and (4)

P_4(g)+10Cl_2(g)\rightarrow 4PCl_5(s)  \Delta H_3=\Delta H_2+\Delta H_4=-1207kJ-628kJ=-1835kJ  

Thus enthaply change for the reaction is -1835 kJ.

3 0
4 years ago
A sample of neon occupies a volume of 478 mL at STP. What will be the volume of the neon when the pressure is reduced to 93.3 kP
Andre45 [30]

The volume of neon when the pressure is reduced to 93.3 kPa is 519 mL.

Explanation:

The kinetic theory of gases is mostly based on Boyle's law. From the Boyle's law, the pressure experienced by any gas molecules is inversely proportional to volume of the gas molecules. Also this inverse relation is obeyed if and only if the number of moles and temperature of the gas molecules remained constant.

So,P=\frac{1}{V}

So if there is a change in pressure then there will be inverse change in volume. That means if there is decrease in the pressure of gas molecules then there will be increase in the volume and vice versa.

So the Boyle's law is combined as P_{1} V_{1} = P_{2} V_{2}

As here the initial pressure or P_{1} is 1 atm or 101.3 kPa and the initial volume is 478 mL. Similarly, the final pressure is 93.3 kPa and the final volume will be

101.3*10^{3}*478*10^{-3}  = 93.3*10^{3} * V_{2}

V_{2} = 519 mL

So, the volume of neon when the pressure is reduced to 93.3 kPa is 519 mL.

5 0
4 years ago
A chemistry student is given 600. mL of a clear aqueous solution at 27.° C. He is told an unknown amount of a certain compound X
DiKsa [7]

Answer: No

Explanation:

Firstly, the molar mass of the dissolved solid is not given. This is necessary to calculate the number of moles present in solution. Secondly, solubility always has to do with temperature and the specified temperature is 27°c and not 21°c. This makes it impossible to calculate the solubility at 21°c. Further information must supplied before the solubility at 21°c can be accurately calculated.

8 0
3 years ago
What is the constant Kc for Cd²+(aq)+4Br-(aq) CdBr4²-(aq)​
Tasya [4]

Answer:

im only in 6th grade TwT

Explanation:

LOL

5 0
3 years ago
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