A rectangular steel block of dimension 100cm × 50m × 20cm has a mass of 450kg. Calculate the density.

The CN– ion is widely used in the synthesis of organic compounds. What is the pattern of electron pairs in this ion? How many bo

OleMash [197]

For the Lewis diagram of the cyanide ion, a figure is shown.

There are 3 pairs of bonding electrons. There is a one lone pair each for the carbon and the nitrogen atoms.

I hope I was able to answer your question. Thank you!

8 0

3 years ago

3. List three structures found in plant cells that are not in ani- mal cells. (7.1.b)

Nikitich [7]

Cell wall, chloroplasts, plasmodesmata,

7 0

3 years ago

If the pressure P applied to a gas is increased while the gas is held at a constant temperature, then the volume V of the gas wi

yuradex [85]

Answer:

For these types of questions the equation that we must take into account is that:

T = PxV (where T is the temperature, P is the pressure and V is the volume) this equation is described as we consider that this is the value N and R is 1, therefore it is not necessary to explain them now.

Explanation:

The quoted equation refers to Boyle's Law, in this law we can explain that the volume increases if the pressure decreases and if the temperature also increases, if the pressure increases and the volume decreases this means that the gas is compressing assuming that the temperature is constant

8 0

3 years ago

Read 2 more answers

Consider the dissolution of AB(s): AB(s)⇌A+(aq)+B−(aq) Le Châtelier's principle tells us that an increase in either [A+] or [B−]

Arlecino [84]

Answer:

A. 0.000128 M is the solubility of M(OH)2 in pure water.

B. $3.23\times 10^{-6} M$ is the solubility of $M(OH)_2$ in a 0.202 M solution of $M(NO_3)_2$ .

Explanation:

A

Solubility product of generic metal hydroxide = $K_{sp}=8.45\times 10^{-12}$

$M(OH)_2\rightleftharpoons M^{2+}+2OH^-$

S 2S

The expression of a solubility product is given by :

$K_{sp}=[M^{2+}][OH^-]^2$

$K_{sp}=S\times (2S)^2=4S^3$

$8.45\times 10^{-12}=4S^3$

Solving for S:

$S=0.000128 M$

0.000128 M is the solubility of M(OH)2 in pure water

B

Concentration of $M(NO_3)_2$ = 0.202 M

Solubility product of generic metal hydroxide = $K_{sp}=8.45\times 10^{-12}$

$M(OH)_2\rightleftharpoons M^{2+}+2OH^-$

S 2S

So, $[M^{2+}]=0.202 M+S$

The expression of a solubility product is given by :

$K_{sp}=[M^{2+}][OH^-]^2$

$8.45\times 10^{-12}=(0.202 M+S)(2S)^2$

Solving for S:

$S=3.23\times 10^{-6} M$

$3.23\times 10^{-6} M$ is the solubility of $M(OH)_2$ in a 0.202 M solution of $M(NO_3)_2$ .

8 0

3 years ago

tert-Butyl alcohol is a solvent with a Kf of 9.10 ∘C/m and a freezing point of 25.5 ∘C. When 0.807 g of an unknown colorless non

Lina20 [59]

Answer:

ethylene glycol (molar mass = 62.07 g/mol).

Explanation:

We can solve this problem using the relation:

ΔTf = Kf.m,

ΔTf is the depression in the freezing point of tert-Butyl alcohol (ΔTf = freezing point of pure solvent - freezing point in presence of unknown liquid = 25.5°C - 15.3°C = 10.2°C).

Kf is the molal freezing point constant of tert-Butyl alcohol (Kf = 9.1 °C/m).

m is the molality of unknown liquid.

∵ ΔTf = Kf.m

∴ m = ΔTf/Kf = (10.2°C)/(9.1 °C/m) = 1.121 m.

We need to calculate the molar mass of the unknown liquid:

Molality (m) is the no. of moles of solute in 1.0 kg of solvent.

∴ m = (mass/molar mass) of unknown liquid/(mass of tert-Butyl alcohol (kg))

m = 1.121 m, mass of unknown liquid = 0.807 g, mass of tert-Butyl alcohol = 11.6 g = 0.0116 kg.

∴ molar mass of unknown liquid = (mass of unknown liquid)/(m)(mass of tert-Butyl alcohol (kg)) = (0.807 g)/(1.121 m)(0.0116 kg) = 62.06 g/mol.

So, the unknown liquid is:

ethylene glycol (molar mass = 62.07 g/mol).

3 0

3 years ago