Explanation:
Given:
x₀ = 0 m
v₀ = 4.2 m/s
t = 11.6 s
a = 2.3 m/s²
Find: x
x = x₀ + v₀ t + ½ at²
x = 0 m + (4.2 m/s) (11.6 s) + ½ (2.3 m/s²) (11.6 s)²
x ≈ 203 m
Round as needed.
Answer: The wheel's average rotational acceleration is -0.4 radians per second squared (rad/s^2)
Explanation: Please see the attachments below
Answer:
B, A, C, D
Explanation:
i hope it helps. im just kinda guessing.
good luck!°°°°°⁰⁰⁰⁰⁰₀₀₀₀₀oo00OO
Answer:
Speed changes at the rate of 24 m/s for each second over time.
Explanation:
We are told the object's acceleration is equal to 24 m/s²
Now we know that acceleration can also be defined as the rate of change of speed with time. Also speed has a unit known as m/s.
Thus, we can rephrase the acceleration in this question to mean;
Speed changes at the rate of 24 m/s for every second with time.
Thrust - Friction = mass * acceleration
Friction = coefficient * mass * gravity
Friction = 0.10 * 75 * 9.8 = 73.5 N
Substituting:
200N - 73.5 = 75a
a = 1.69 m/s^2
Obtaining final velocity at the end of 41 seconds:
Vf = at
Vf = 1.69 (41)
Vf = 69.15 m/s
Using the formula for displacement for linear motion problems:
s = Vo*t + (1/2)a*t^2
s = 0 + (1/2)(1.69)(41^2)
s = 1420.445 meters
After he runs out of fuel, we use the following formula to find the distance that he coasts:
F = ma = coefficient*m*g
a = 0.10(9.8)
a = -0.98
Vf^2 = Vo^2 + 2as
0 = 69.15^2 + 2(-0.98)s
s = 2439. 65
Adding the 2 displacements together to obtain the total distance:
Total distance = 2439.65 + <span>1420.45 meters
Total distance = 3860.1 meters</span>