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Gre4nikov [31]
3 years ago
6

Everyone is trying to living a perfect life via social media.

Physics
1 answer:
Stells [14]3 years ago
7 0

Answer:

wdym?

is this a question?

Explanation:

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An electric motor rotates 60 times per second if the alternating current source is 60 Hz. How many times will an electric motor
valentina_108 [34]

Answer:

180,000

Explanation:

Frequency is a quantity that is measured in Hertz [Hz] and it represents the number of rotations per second.

A motor with a frequency of 50 Hz will rotate 50 times per second.

Since we don't want to know how many times it rotates per second, but per hour. The first step is to find how many seconds there are in an hour and then multiply that amount by 50.

Seconds in an hour:

there are 60 seconds per minute, and 60 minutes per hour, thus there are

60*60 = <u>3,600 seconds in an hour</u>

We know that the motor will rotate 50 times per second so to find the number of rotations in 1 hour =  3,600 seconds we multiply:

50*3,600 = 180,000 rotations

8 0
3 years ago
The first step when doing<br> an<br> investigation is the observe a situation. True or false?
Sunny_sXe [5.5K]

Answer:

True! First step is to make objective observations.

6 0
3 years ago
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HELP!!! Why is plasma considered the most common state of matter in the universe?
olasank [31]

Clue : There is plasma in sun

4 0
2 years ago
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А______<br> is a unit of measurement for energy. (7 Letters)
a_sh-v [17]

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Joule or kilowatt/hour

7 0
2 years ago
If the magnitude of the magnetic field is 6.50 mT at a distance of 12.8 cm from a long straight current carrying wire, what is t
Lunna [17]

Answer: magnitude of the magnetic field at a distance of 19.4 cm from the wire=4.29mT

Explanation:

According to  Biot-Savart law, A magnetic field generated by a current  carrying wire at a distance is represented as

B=μ₀I/ 2πr

B = magnetic field intensity 1000 mT =1T, 6.50mT = 6.50 X 10^-3T

 μ₀ =permeability of free space  4π × 10−7 H/m

I = current intensity

r = radius, 100cm = 1m, 12.8 cm= 12.8 x 10^-2m

6.50 X 10^-3 =  μ₀ x I/ 2 π X 12.8 X 10^-2

I =6.50  X 10 ^-3 X 2π  X  X 12.8 X 10^-2/  4π × 10−7 H/m

I= 4160 A

when the magnetic field is at 19.4 cm from the wire

B=μ₀I/ 2πr

= 4π × 10−7 H/m x4160/ 2π x 19.4 x 10^-2

=0.004288

= 4.29x 10 ^-3T

= 4.29mT

7 0
3 years ago
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