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Gemiola [76]
3 years ago
5

If the moon disappeared what effect would this have on the earths tides

Physics
2 answers:
iogann1982 [59]3 years ago
4 0
The moon has a huge impact on the tides. With the Moon gone, the oceans would become much calmer. The Sun still has its effect on them known as the solar tides. Surfers wouldn't be completely devoid of waves. 
Sliva [168]3 years ago
3 0

There would no longer be any tides.

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Nicolaus Copernicus was a Polish astronomer who is best known for the theory that the sun is near the center of the universe and
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Answer:

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3 years ago
The gamma ray released by each decay carries 140kev of energy. find the total energy e released by decays in the 2 hours.
olya-2409 [2.1K]
First, we would need to know the decaying isotope.
Next, we use the decay formula
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3 years ago
Read 2 more answers
A small loop of area A = 5.5 mm2 is inside a long solenoid that has n = 919 turns/cm and carries a sinusoidally varying current
Tema [17]

Answer:410.90\times 10^{-6} V

Explanation:

Given

A=5.5 mm^2

n=919 turns/cm\approx 85400 turns/m

\omega =226 rad/s

According to the Faraday law of induction, induced emf is given by

E=-\frac{\mathrm{d} \phi _B}{\mathrm{d} t}

Magnetic field \phi _B=B\cdot A

B=\mu _0ni=\mu _0ni_osin\left ( \omega t\right )

B=4\pi \times 10^{-7}\times 85400\times 3.08\times \sin (226t)

B=0.3305\sin (226t)

\phi _{B}=0.3305\times \sin (226t)\times 5.5\times 10^{-6}

\phi _{B}=1.818\times 10^{-6}\sin (226t)

E=-\frac{\mathrm{d} \phi _B}{\mathrm{d} t}

E=-1.818\times 10^{-6}\times 226\cos (226t)

E=-410.90\times 10^{-6}\cos (226t)

Amplitude of EMF induced=410.90\times 10^{-6} V

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4 years ago
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Travka [436]

Wavelength = (speed) / (frequency)

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