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Phoenix [80]
3 years ago
9

A pitcher throws a 0.15 kg baseball so that it crosses home plate horizontally with a speed of 10 m/s. It is hit straight back a

t the pitcher with a final speed of 24 m/s. Assume the direction of the initial motion of the baseball to be positive.
Physics
1 answer:
Maru [420]3 years ago
4 0

Answer:

-5.1 kg m/s

Explanation:

Impulse is the change in momentum.

Change in momentum= final momentum - initial momentum=mv_{2} +mv_{1}

Plugging in the values= -0.15*24 - (0.15*10) (The motion towards the pitcher is negative as the initial motion is considered to be positive)

Impulse=-5.1 kg m/s (-ve means that it is the impulse towards the pitcher)

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Explanation:

It is given that,

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Part B,

The initial rotational kinetic energy is given by :

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k_f=\dfrac{1}{2}\times (900+70\times (2.9)^2)(0.574)^2

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