Question

Find the area of a triangle bounded by the y axis, the line f(x)=9−2/3x, and the line is perpendicular to f(x) that passes through the origin. Area=

Answer 1

Answer:

Step-by-step explanation:

Equation of the line perpendicular to f(x) that passes through origin:

$g(x)= \frac{3}{2}x$

Intersection point:

$9-\frac{2}{3}x=\frac{3}{2}x$

$x=\frac{27}{13}$, $y= \frac{51}{26}$

Triangle formed with vertex A (0,9), O(0,0), and C (27/13, 51/26).

The height of the triangle is 27/13 with respect to the base OA

Now, the leftover is just applying the formula to find the area of the triangle.

I let you finish your own work. Good luck