First, we need to find the amount of winks in an hour, to simplify it so we can answer easier. Since there are 60 minutes in an hour, we can multiply 5 by 60 to find the number of winks in an hour.
5*60=300
Now multiply 300 by 8.
300*8=2,400
She winks exactly 2,400 times per day.
Hope this helps!
Answer:
The minimum concentration of sodium sulfate required to producer precipitation is .
Explanation:
Concentration of barium chloride=
Concentration of barium ions =
1 mol of barium chloride gives 1 mol of barium ions.
The solubility product for barium sulfate=
0.019 M S
The expression of solubility product for barium sulfate:
The minimum concentration of sulfate ions =
1 mole of sulfate ions are proceed form 1 mole of sodium sulfate solution.
Then sulfate ions will be obtained from:
of sodium sulfate
The minimum concentration of sodium sulfate required to producer precipitation is .
= 6.42 × 10²²
(scientific notation)
= 6.42e22
(scientific e notation)
= 64.2 × 10²¹
(engineering notation)
(sextillion; prefix zetta- (Z))
= 64200000000000000000000
(real number)
Answer: 18 g
Explanation:
The option closest to this is <u>18 g</u>
<span>1.16 moles/liter
The equation for freezing point depression in an ideal solution is
ΔTF = KF * b * i
where
ΔTF = depression in freezing point, defined as TF (pure) ⒠TF (solution). So in this case ΔTF = 2.15
KF = cryoscopic constant of the solvent (given as 1.86 âc/m)
b = molality of solute
i = van 't Hoff factor (number of ions of solute produced per molecule of solute). For glucose, that will be 1.
Solving for b, we get
ΔTF = KF * b * i
ΔTF/KF = b * i
ΔTF/(KF*i) = b
And substuting known values.
ΔTF/(KF*i) = b
2.15âc/(1.86âc/m * 1) = b
2.15/(1.86 1/m) = b
1.155913978 m = b
So the molarity of the solution is 1.16 moles/liter to 3 significant figures.</span>