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natka813 [3]
2 years ago
13

Jshsbdbfbbbfffbbdvdvsgssggdhdh

Chemistry
1 answer:
11Alexandr11 [23.1K]2 years ago
8 0
Very nice english.......
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The reaction H2SO4 + 2 NaOH -> Na2SO4 + 2H2O represents an acid-base tritration. The equivalence point occurs when 24.75 mL o
artcher [175]
            moles NaOH = c · V = 0.2432 mmol/mL · 24.75 mL = 6.0192 mmol
            moles H2SO4 = 6.0192 mmol NaOH · 1 mmol H2SO4 / 2 mmol NaOH = 3.0096 mmol
Hence
            [H2SO4]= n/V = 3.0096 mmol / 38.94 mL = 0.07729 M
The answer to this question is  [H2SO4] = 0.07729 M

6 0
3 years ago
When 125 mL of 0.150 M Pb(NO3)2 is mixed with 145 mL of 0.200 M KBr, 4.92 g of PbBr2 is collected. Calculate the percent yield.
Semenov [28]

Answer:

Y = 92.5 %

Explanation:

Hello there!

In this case, since the reaction between lead (II) nitrate and potassium bromide is:

Pb(NO_3)_2+2KBr\rightarrow PbBr_2+2KNO_3

Exhibits a 1:2 mole ratio of the former to the later, we can calculate the moles of lead (II) bromide product to figure out the limiting reactant:

0.125L*0.150\frac{molPb(NO_3)_2}{L} *\frac{1molPbBr_2}{1molPb(NO_3)_2} =0.01875molPbBr_2\\\\0.145L*0.200\frac{molKBr}{L} *\frac{1molPbBr_2}{2molKBr} =0.0145molPbBr_2

Thus, the limiting reactant is the KBr as it yields the fewest moles of PbBr2 product. Afterwards, we calculate the mass of product by using its molar mass:

0.0145molPbBr_2*\frac{367.01gPbBr_2}{1molPbBr_2} =5.32gPbBr_2

And the resulting percent yield:

Y=\frac{4.92g}{5.32g} *100\%\\\\Y=92.5\%

Regards!

4 0
3 years ago
How many atoms are there in one mole of carbon ? (Show Work)
bixtya [17]

6.022 x 10^23, this is avogados number, a mole has 6.022 x 10^23 of anything, but in this instance, it is 6.022 x10^23 atoms of carbon.

8 0
3 years ago
4. The left brain does all of the following EXCEPT_
Crazy boy [7]

Answer: D arts

Explanation: The left part of your brain does logic, science, language, and mathematics, the right part of your brain does creativity and arts.

8 0
3 years ago
A sample of octane burns releasing 2290 J of heat to the surroundings, and the gases produced expands against a piston to do 560
dexar [7]

<u>Answer:</u> The internal energy change for the reaction is -2850 J

<u>Explanation:</u>

  • <u>Sign convention of heat:</u>

When heat is absorbed, the sign of heat is taken to be positive and when heat is released, the sign of heat is taken to be negative.

  • <u>Sign convention of work:</u>

Work done for expansion process is taken as negative and work done for compression is taken as positive.

According to the First law of thermodynamics,

\Delta U=q+w

where,

\Delta U = internal energy

q = heat absorbed or released  = -2290 J

w = work done = -560 J

Putting values in above equation, we get:

\Delta U=(-2290)+(-560)\\\\\Delta U=-2850J

Hence, the internal energy change for the reaction is -2850 J

4 0
3 years ago
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