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EleoNora [17]
3 years ago
12

El agua de una alberca requiere de 35.8 gramos de desinfectante (NaClO), por cada 1000 L de agua para mantenerse limpia. El día

de hoy el cuidador de la alberca no fue a trabajar y dejó al velador encargado de la adición de desinfectante al agua, pero al velador se le olvidó la cantidad y le agregó 65 g.
Chemistry
1 answer:
coldgirl [10]3 years ago
8 0

Answer:

816L adicionales para mantener la concentración

Explanation:

<em>Cuánta agua debe adicionar el cuidador para que se mantenga la concentración del desinfectante?</em>

<em />

El desinfectante, NaClO, idealmente debe estar en una concentración de:

35.8g / 1000L = 0.0358g/L

Como el velador agregó 65g de desinfectante, la cantidad de agua necesaria es:

65g * (1L / 0.0358g) = 1816L de agua son necesarios

Asumiendo que el velador agregó 1000L, el cuidador debe agregar:

1816L - 1000L =

<h3>816L adicionales para mantener la concentración</h3>

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Answer: elevation , The boundaries of a watershed are determined by topography, which is the shape or the physical features of the land's surface. If the highest points of land surrounding a river were connected (like “connect-the-dots”), this line would form the watershed boundary.

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3 years ago
How to calculate the sum of the ratio of the ions
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If it is just ratio you must just put the mass number on the either side of the symbol ‘:’ and cancel but the same process is not used to find simplest ratio
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3 years ago
g Calculate the theoretical yield (in grams) of your product if you start with 0.50 grams of E-stilbene. The molecular weight of
sattari [20]

Answer:

0.9433g

Explanation:

Theoretical yield is defined as the mass produced assuming all reactant reacts producing the product.

Assuming the reaction is 1:1, we need to find the moles of E-stilbene (Reactant). If all reactant reacts, the moles of E-stilbene = Moles of product.

Using the molar mass of the product we can find the theoretical yield as follows:

<em>Moles E-stilbene:</em>

0.50g * (1mol/180.25g) = 0.00277 moles = Moles Product

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4 0
3 years ago
Calculate [H3O+] and [OH−] for each of the following solutions at 25 ∘C given the pH. pH= 8.74, pH= 11.38, pH= 2.81
Gnom [1K]

Answer:

Explanation:

Given parameters;

pH  = 8.74

pH = 11.38

pH = 2.81

Unknown:

concentration of hydrogen ion and hydroxyl ion for each solution = ?

Solution

The pH of any solution is a convenient scale for measuring the hydrogen ion concentration of any solution.

It is graduated from 1 to 14

      pH = -log[H₃O⁺]

      pOH = -log[OH⁻]

 pH + pOH = 14

Now let us solve;

   pH = 8.74

             since  pH = -log[H₃O⁺]

                           8.74 =  -log[H₃O⁺]

                           [H₃O⁺] = 10⁻^{8.74}

                             [H₃O⁺]  = 1.82 x 10⁻⁹mol dm³

       pH + pOH = 14

                 pOH = 14 - 8.74

                  pOH = 5.26

                  pOH = -log[OH⁻]

                     5.26  = -log[OH⁻]

                     [OH⁻] = 10^{-5.26}

                      [OH⁻] = 5.5 x 10⁻⁶mol dm³

2.  pH = 11.38

             since  pH = -log[H₃O⁺]

                           11.38 =  -log[H₃O⁺]

                           [H₃O⁺] = 10⁻^{11.38}

                             [H₃O⁺]  = 4.17 x 10⁻¹² mol dm³

           pH + pOH = 14

                 pOH = 14 - 11.38

                  pOH = 2.62

                  pOH = -log[OH⁻]

                     2.62  = -log[OH⁻]

                     [OH⁻] = 10^{-2.62}

                      [OH⁻] =2.4 x 10⁻³mol dm³

3. pH = 2.81

             since  pH = -log[H₃O⁺]

                           2.81 =  -log[H₃O⁺]

                           [H₃O⁺] = 10⁻^{2.81}

                             [H₃O⁺]  = 1.55 x 10⁻³ mol dm³

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                 pOH = 14 - 2.81

                  pOH = 11.19

                  pOH = -log[OH⁻]

                     11.19  = -log[OH⁻]

                     [OH⁻] = 10^{-11.19}

                      [OH⁻] =6.46 x 10⁻¹²mol dm³

5 0
3 years ago
The reaction of a quantity of sulfur trioxide with water gives an acid with a volume of 2 l, containing 1.8 mol of the dissolved
777dan777 [17]

Answer :]

A.)Calculate the mass of ammonium sulfate that would be obtained by reacting with ammonia acid.

<em>Correct me if i'm wrong :]</em>

8 0
2 years ago
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