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almond37 [142]
2 years ago
6

Determine two numbers that have a product of 40 but have a sum of 13.

Mathematics
1 answer:
Paha777 [63]2 years ago
8 0

Answer:

The two numbers are 8 and 5.

Step-by-step explanation:

Let consider x and y to be these two numbers.

So;

(x) * (y) = 40 ---- (1)

x + y     = 13 ----- (2)

From (2), let x =  13 - y

Then;

(13 - y) * y = 40

13y - y² = 40

13y - y² - 40 = 0

-y² + 13y - 40 = 0

Multiply through by (-)

y² - 13y + 40 = 0

By factorization;

(y - 8) (y - 5) = 0

y = 8 or  y = 5

CHECK:

8 * 5 = 40

8 + 5 = 13

Therefore, the two numbers are 8 and 5.

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Answer:

x = 2

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Step-by-step explanation:

2x(10) = 8(x+3)

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subtract 8x from both sides

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x = 2

Check:

4(10) = 8(5)

40 = 40

Correct

2x = 2 x 2 = 4

4 + 10 = 14

If my answer is incorrect, pls correct me!

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Answer:

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3 years ago
Five sevenths times seven thirds
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A wildflower bouquet costs $4.25 at the farmer's market. A vase can be purchased for an additional $3.50. Kelly has $20 to buy a
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Answer:

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