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ddd [48]
3 years ago
5

if an electron is released during radioactive decay which type of Decay has taken place a gamma decay b beta decay c electromagn

etic decay d alpha decay​
Chemistry
2 answers:
Pavel [41]3 years ago
6 0

Assuming you can only pick one answer, the best answer would be beta decay (choice B).

olasank [31]3 years ago
3 0

Answer:

hi

i hope you have a great day!

Explanation:

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N= m/Mr Find the Mr of C3H8NO5P and then divide the mass by the Mr. Sorry I don't have periodic table with me so I can't calculate the Mr for you
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What common household element can, over time, reduce airflow, insulate components, reduce heat exchange or even cause the system
lina2011 [118]

Answer:

The correct answer is Dust

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4 0
3 years ago
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A cube of an unknown metal measures 0.200 cm on one side. The mass of the cube is 52 mg. Which of the following is most likely t
Margarita [4]

Answer:

Option E. Zirconium

Explanation:

From the question given above, the following data were obtained:

Length of side (L) of cube = 0.2 cm

Mass (m) of cube = 52 mg

Name of the unknown metal =?

Next, we shall determine the volume of the cube. This can be obtained as follow:

Length of side (L) of cube = 0.2 cm

Volume (V) of the cube =?

V = L³

V = 0.2³

V = 0.008 cm³

Next, we shall convert 52 mg to g. This can be obtained as follow:

1000 mg = 1 g

Therefore,

52 mg = 52 mg × 1 g / 1000 mg

52 mg = 0.052 g

Thus, 52 mg is equivalent to 0.052 g.

Next, we shall determine the density of the unknown metal. This can be obtained as follow:

Mass = 0.052 g.

Volume = 0.008 cm³

Density =?

Density = mass / volume

Density = 0.052 / 0.008

Density of the unknown metal = 6.5 g/cm³

Comparing the density of the unknown metal i.e 6.5 g/cm³ with those given in table in the above, we can conclude that the unknown metal is zirconium

7 0
3 years ago
How many atoms are equal to 1.5 moles of hellium
ANTONII [103]

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Explanation:

6 0
2 years ago
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Calculate the empirical formula for DCBN, given that the percent composition is 48.9%C, 1.76%H, 41.2%Cl, and 8.15%N.
sweet [91]

Answer:

empirical formula is C7H3NCl2

Explanation:

too much work too explain and im lazy

5 0
3 years ago
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