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iris [78.8K]
3 years ago
7

What is the physical state of helium at room temperature

Chemistry
1 answer:
Artyom0805 [142]3 years ago
3 0
Depending on the exact room temp, say the helium is in a plastic (one of the ones you buy already full of helium) balloon. Now, you should notice the balloon may be a little squishy, but it is still afloat and looking happy. If you took it outside on a cold day, it would deflate, but when you take it back inside where it is warm, it will reinflate. This is called Boyle's Law. Think if it as if the Helium molecules are partying in the balloon, but when they go out in the cold, they huddle together for warmth.
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How much does 0.0273 moles of Na2O weigh
devlian [24]

Answer:

1.69 g Na₂O

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

0.0273 mol Na₂O

<u>Step 2: Identify Conversions</u>

Molar Mass of Na - 22.99 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Na₂O - 2(22.99) + 16.00 = 61.98 g/mol

<u>Step 3: Convert</u>

<u />0.0273 \ mol \ Na_2O(\frac{61.98 \ g \ Na_2O}{1 \ mol \ Na_2O} ) = 1.69205 g Na₂O

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

1.69205 g Na₂O ≈ 1.69 g Na₂O

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Explanation:

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A single covalent bond involves two atoms sharing one pair of electrons.<br><br> True<br> False
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How many Joules of heat will be given off by 55.0g of water as it cools from 87.3°C to 25.0°C?
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Answer:

Q = -14322.77 J

Explanation:

Given data:

Mass of water = 55.0 g

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Final temperature = 25.0 °C

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Solution:

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It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Specific heat capacity of water is 4.18 J/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

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ΔT = 25.0 °C - 87.3°C

ΔT = - 62.3 °C

Q = 55.0 g×4.18 J/g.°C × - 62.3 °C

Q = -14322.77 J

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