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2 years ago

Define energy and power and describe the relationship that exists between them.

Chemistry

1 answer:

bagirrra123 [75]2 years ago

4 0

Energy is ability to work or function. Power is the amount of energy transferred to an object.
When energy is transferred to an object or has energy it moves and power is the energy put in a object, meaning they work together to move the object

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How many grams are in 5 mols of KOH

elena55 [62]

Answer:

0.08911760029829444

Explanation:

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2 years ago

A farmer uses water to irrigate his potato crops. Which roles of water does this examplify

exis [7]

Answer:

This exemplifies the agricultural role of water.

Explanation:

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3 years ago

What is the area of triangle ABC with vertices A(x¹,y¹), B(x²,y²)and C (x³,y³)??????????<br>

AlexFokin [52]

Answer:

$Area = \frac{1}{2}|x_1(y_2 - y_3)+x_2(y_3 - y_1)+x_3(y_1 - y_2)|$

$Area = 2\ units^2$

Explanation:

Given

$A = (x_1,y_1)$

$B = (x_2,y_2)$

$C = (x_3,y_3)$

Required

Determine the area

The area of a triangle is :

$Area = \frac{1}{2}|A_x(B_y - C_y) + B_x(C_y - A_y) + C_x(A_y - B_y)|$

By substituting values for the x and y coordinates of A, B and C;

We have:

$Area = \frac{1}{2}|x_1(y_2 - y_3)+x_2(y_3 - y_1)+x_3(y_1 - y_2)|$

So:

For instance

$A = (0,3)$

$B= (2,1)$

$C = (2,3)$

The area is:

$Area = \frac{1}{2}|0(1-3) + 2(3-3) + 2(3-1)|$

$Area = \frac{1}{2}| 2*0 + 2*2|$

$Area = \frac{1}{2}| 0 + 4|$

$Area = \frac{1}{2}|4|$

$Area = \frac{1}{2} * 4$

$Area = 2\ units^2$

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2 years ago

What can you say about the strength of the intermolecular forces in neon and argon based on the critical points of Ne and Ar? (c

algol13

Explanation:

Since, it is given that critical temperature of Argon is 150.9 K and critical pressure of Argon is 48.0 atm.

It is known that gas phase of neon occurs at 50 K. As the boiling point of Ar is more than the boiling point of neon which means that there is strong intermolecular force of attraction between argon molecules as compared to neon molecules.

This is also because argon is larger in size. As a result, induced dipole-induced dipole forces leads to more strength in Ar as compared to Ne.

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kvv77 [185]

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