Question

Complete and balance the molecular equation, including the phases, for the reaction of aqueous potassium sulfate, k2so4, and aqueous strontium iodide, sri2.

Answer 1

The balanced molecular equation between ${{\mathbf{K}}_{\mathbf{2}}}{\mathbf{S}}{{\mathbf{O}}_{\mathbf{4}}}$ and ${\mathbf{Sr}}{{\mathbf{I}}_{\mathbf{2}}}$ is as follows:

$\boxed{{{\text{K}}_{\text{2}}}{\text{S}}{{\text{O}}_4}\left({aq}\right)+{\text{Sr}}{{\text{I}}_2}\left({aq}\right)\to2{\text{KI}}\left({aq}\right)+{\text{SrS}}{{\text{O}}_4}\left(s\right)}$

Further explanation:

The chemical reaction that contains an equal number of atoms of the different elements in the reactant as well as in the product side is known as a balanced chemical reaction. The chemical equation is required to be balanced to follow the Law of the conservation of mass.

The steps to balance a chemical reaction are as follows:

Step 1: Complete the reaction and write the unbalanced symbol equation.

In the reaction, ${{\text{K}}_{\text{2}}}{\text{S}}{{\text{O}}_4}$ reacts with ${\text{Sr}}{{\text{I}}_2}$ to form KI and ${\text{SrS}}{{\text{O}}_4}$. ${{\text{K}}_{\text{2}}}{\text{S}}{{\text{O}}_4}$, ${\text{Sr}}{{\text{I}}_2}$ and KI

exist in the aqueous phase while the physical state of ${{\text{H}}_{\text{2}}}{\text{O}}$ is liquid. The unbalanced chemical equation is as follows:

${{\text{K}}_{\text{2}}}{\text{S}}{{\text{O}}_4}\left({aq}\right)+{\text{Sr}}{{\text{I}}_2}\left({aq}\right)\to{\text{KI}}\left({aq}\right)+{\text{SrS}}{{\text{O}}_4}\left(s\right)$

Step 2: Then we write the number of atoms of all the different elements that are present in a chemical reaction in the reactant side and product side separately.

• On reactant side,

Number of potassium atoms is 2.

Number of sulfur atom is 1.

Number of oxygen atoms is 4.

Number of strontium atom is 1.

Number of iodine atoms is 2.

• On the product side,

Number of potassium atom is 1.

Number of sulfur atom is 1.

Number of oxygen atoms is 4.

Number of strontium atom is 1.

Number of iodine atom is 1.

Step 3: Initially, we try to balance the number of other atoms of elements except for carbon, oxygen, and hydrogen by multiplying with some number on any side. Sulfur and strontium atoms are balanced on both sides. To balance the number of potassium and iodine atoms multiply KI by 2. Now the reaction is,

${{\text{K}}_{\text{2}}}{\text{S}}{{\text{O}}_4}\left({aq}\right)+{\text{Sr}}{{\text{I}}_2}\left({aq}\right)\to\boxed2{\text{KI}}\left({aq}\right)+{\text{SrS}}{{\text{O}}_4}\left(s\right)$

Step 4: After this, we balance the number of atoms of carbon and then hydrogen atom followed by oxygen atoms. The number of oxygen atoms is balanced on both sides. Now the reaction is,

${{\text{K}}_{\text{2}}}{\text{S}}{{\text{O}}_4}\left({aq}\right)+{\text{Sr}}{{\text{I}}_2}\left({aq}\right)\to2{\text{KI}}\left({aq}\right)+{\text{SrS}}{{\text{O}}_4}\left(s\right)$

Step 5: Finally, we check the number of atoms of each element on both sides. If the number is same then the chemical equation is balanced. The balanced chemical equation is as follows:

${{\text{K}}_{\text{2}}}{\text{S}}{{\text{O}}_4}\left({aq}\right)+{\text{Sr}}{{\text{I}}_2}\left({aq}\right)\to2{\text{KI}}\left({aq}\right)+{\text{SrS}}{{\text{O}}_4}\left(s\right)$

Learn more:

1. Balanced chemical equation: brainly.com/question/1405182

2. Identify the precipitate in the reaction: brainly.com/question/8896163

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Chemical reaction and equation

Keywords: Balancing, K2SO4, SrI2, KI, SrSO4, sulfur, oxygen, potassium, iodine, strontium, physical state, solid, aqueous, coefficients, balanced chemical reaction, reactant side, product side.

Answer 2

The reaction between K₂SO₄(aq) and SrI₂(aq) produces KI(aq) and SrSO₄(s) as products. 

The reaction is 
K₂SO₄(aq) + SrI₂(aq) → KI(aq)+ SrSO₄(s) 

To balance the equation both side of the reaction should have same number of atoms in each element.

Right hand side of the reaction has 1 K, 1 I, 1 Sr, 1 S and 4 O atoms while 2 K, 2 I, 1 Sr,1 S and 4 O present in left hand side of the reaction. 
Hence, number of I atoms and number of K atoms are not balanced. 
To balance the K atoms we should add 2 before KI. Then I atoms will be 2 at the right hand side. 

Hence, the balanced reaction equation is
K₂SO₄(aq) + SrI₂(aq) → 2KI(aq)+ SrSO₄(s)