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3 years ago

What is the [SO32-) in the 0.080 M H2SO3 .080 M Solution?

Chemistry

1 answer:

slega [8]3 years ago

4 0

Answer:

0.080 M

Explanation:

From the question given above, the following data were obtained:

Concentration of H₂SO₃ = 0.080 M

Concentration of SO₃²¯ =…?

The concentration of SO₃²¯, can be obtained as follow:

H₂SO₃ (aq) <==> 2H⁺ (aq) + SO₃²¯ (aq)

From the balanced equation for above,

1 mole of H₂SO₃ produced 1 mole of SO₃²¯.

Therefore, 0.080 M H₂SO₃ will also produce 0.080 M SO₃²¯.

Thus, the concentration of SO₃²¯ is 0.080 M

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4 years ago

You have 16.0 g of some compound and you perform an experiment to remove all of the oxygen, 11.2 g of iron is left. What is the

oksian1 [2.3K]

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<h3>Empirical formula</h3>

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3 years ago

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Total initial moles of EDTA = 0.0600 M × 0.025 L

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= 0.0015 - 0.000616

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Molarity of $V^{3+}$ solution = $\frac{\text{moles}}{\text{volume (L)}}$

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3 years ago

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