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natka813 [3]
3 years ago
9

What is the difference between a terrestrial planet and a gas giant

Chemistry
1 answer:
luda_lava [24]3 years ago
6 0

Gas Giants are usually bigger than Terrestrial Planets. Gas Giants also have thicker atmospheres, and have gaseous surfaces. Terrestrial planet tend to be smaller, and have solid surfaces. In our solar system, Mercury, Venus, Earth (home), and Mars are Terrestrial planets.  While Jupiter, Saturn, Uranus (the planet), and Neptune are Gas Giants. Gas Giants are also known as Jovian planets.

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Which statement describes J.J. Thomson’s plum-pudding model of the atom?
ra1l [238]
Option C: the electrons are embedded in a positive sphere.

As we know that was a wrong model and nowadays the electrons are considered to be around the nucleus, in regions called orbitals.
4 0
3 years ago
What is the number of cations is present in 1.17 g of sodium chloride? Given Na=6*10power 23 mol
natita [175]
1.17×6×1023 Wich equals 7.02×1023 Your final answer is 7.02×1023
5 0
3 years ago
Read 2 more answers
How is the way a mixture is combined different from how a compound is combined?
artcher [175]

Mixture is composed of molecules of different types. A compound can only be separated through chemical means. While a compound is a pure substance that contains 2 or more elements chemically combined together while a mixture are formed when two substances are added together without chemical bonds being formed.

7 0
3 years ago
Use the following half-reactions to construct a voltaic cell:
velikii [3]

<u>Answer:</u> The correct answer is 3Ag^+(aq.)+Cr(s)\rightarrow 3Ag(s)+Cr^{3+}(aq.);E^o_{cell}=+1.53V

<u>Explanation:</u>

We are given:

Cr^{3+}(aq.)+3e^-\rightarrow Cr(s);E^o=-0.73V\\\\Ag^+(aq.)+e^-\rightarrow Ag(s);E^o=+0.80V

The substance having highest positive E^o potential will always get reduced and will undergo reduction reaction. Here, silver will always undergo reduction reaction will get reduced.

Chromium will undergo oxidation reaction and will get oxidized.

The half reactions for the above cell is:

Oxidation half reaction: Cr(s)\rightarrow Cr^{3+}+3e^-;E^o_{Cr^{3+}/Cr}=-0.73V

Reduction half reaction: Ag^{+}+e^-\rightarrow Ag(s);E^o_{Ag^{+}/Ag}=0.80V       ( × 3)

Net equation:  3Ag^+(aq.)+Cr(s)\rightarrow 3Ag(s)+Cr^{3+}(aq.)

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

Putting values in above equation, we get:

E^o_{cell}=0.80-(-0.73)=1.53V

Hence, the correct answer is 3Ag^+(aq.)+Cr(s)\rightarrow 3Ag(s)+Cr^{3+}(aq.);E^o_{cell}=+1.53V

4 0
3 years ago
A gas occupies a volume of 0.2 L at 176 mm Hg. What volume will the gas occupy at 760 mm Hg?
nignag [31]

Answer:

V_2=0.046L

Explanation:

Hello,

In this case, we apply the Boyle's law as an inversely proportional relationship allowing us to understand the pressure-volume behavior as shown below:

P_1V_1=P_2V_2

In such a way, solving for the final volume V2, we obtain:

V_2=\frac{P_1V_1}{P_2}=\frac{0.2L*176mmHg}{760mmHg}  \\\\V_2=0.046L

Best regards.

8 0
2 years ago
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