CAN SOMEONE HELP ME ITS DUE IN 5 MINS!!

Mathematics

1 answer:

Alex73 [517]3 years ago

7 0

Answer:

Small Tray: 11

Large Tray: 14

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A major department store chain is interested in estimating the average amount its credit card customers spent on their first vis

SSSSS [86.1K]

Answer: (39.424, 61.576)

Step-by-step explanation:

When population standard deviation( $\sigma$ ) unknown ,The confidence interval for population mean is given by :-

$\overline{x}\pm t^*\dfrac{s}{\sqrt{n}}$

, where n= Sample size

$\overline{x}$ = sample mean.

s= sample standard deviation

$t^*$ = Critical t-value (two-tailed)

Given : n= 15

Degree of freedom= 14 [df=n-1]

$\overline{x}=\ $50.50$

$s^2=400\\\\\Rightarrow\ s=\sqrt{400}=20$

Significance level = $\alpha=1-0.95=0.05$

For $\alpha=0.05$ and df = 14, the critical t-values : $t^*=\pm2.1448$

Then the 95% confidence interval for population mean will be :

$50.50\pm (2.1448)\dfrac{20}{\sqrt{15}}\\\\=50.50\pm(2.1448)(5.1640)\\\\\approx50.50\pm11.076\\\\=(50.50-11.076,\ 50.50+11.076)\\\\=(39.424,\ 61.576)$

Hence, a 95% confidence interval for the average amount its credit card customers spent on their first visit to the chain's new store in the mall. : (39.424, 61.576)

6 0

4 years ago

Santana Office Supplies record the number of times their five photocopiers break down.

g100num [7]

Answer:

125

Step-by-step explanation:

You add all the breakdowns up together to get the total.

15+21+34+32+23 = 125

6 0

3 years ago

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