Answer:
(-3,-13)
Step-by-step explanation:
...................
Answer:
(a) ln(x) = 0
Then 0 < x < 1
(b) e^x > 2
Then ln2 < x < ∞
(a) ln(3x - 17) = 5
x = 55.1377197
ln(a + b) + ln(a - b) - 5ln(c)
= ln[(a² - b²)/c^5]
Step-by-step explanation:
First Part.
(a) ln(x) < 0
=> x < e^(0)
x < 1 ....................................(1)
But the logarithm of 0 is 1, and the logarithm of negative numbers are undefined, we can exclude the values of x ≤ 0.
In fact the values of x that satisfy this inequalities are between 0 and 1.
Therefore, we write:
0 < x < 1
(b) e^x > 2
This means x > ln2
and must be finite.
We write as:
ln2 < x < ∞
Second Part.
(a) ln(3x - 17) = 5
3x - 17 = e^5
3x = 17 + e^5
x = (1/3)(17 + e^5)
= 55.1377197
Third Part.
We need to write
ln(a + b) + ln(a - b) - 5ln(c)
as a single logarithm.
ln(a + b) + ln(a - b) - 5ln(c)
= ln(a + b) + ln(a - b) - ln(c^5)
= ln[(a + b)(a - b)/(c^5)]
= ln[(a² - b²)/c^5]
Answer:
Step-by-step explanation:
Given the following probabilities for events A and B
We want to find P(A ∪ B ∪ C).
Using the inclusion/exclusion formula for the union of three events:
P(A ∪ B ∪ C) = P(A) + P(B) + P(C) − P(A ∩ B) − P(A ∩ C)−P(B∩C)+P(A∩B∩C).
Therefore, P(A or B or C) = 0.48
I assume your "reasons" mean "roots" or "zeros"
if 3 is a root, plug x=3 in the equation, you can find n:
3²+(n-1)*3+6=0
3(n-1)=-15
n-1=-5
n=-4
Plug n=-4 in the original equation: x²-5x+6=0
factor: (x-3)(x-2)=0
x=3, which we already know
or x=2, which is the value of m+4
m+4=2
m=-2
Answer: pizza and cheese
Step-by-step explanation :
