Hhczfik in nb vguiigdr 5th hb. jigfddtjnbvt
First find slope
5-10/-1-0= 5
find y-intercept
10=5(0)+B
b=-10
equation: y=5x-10
The rate a computer works is 1/time. Working together, you add the rates.
Let new computer be x, old computer be y.
x = y - 7
Rounded to nearest tenth gives:
x = 23 hours
Cosecant = hypotenuse / opposite side ( that is 1 / sine)
csc C = AC / 8
AC = sqrt (6^2 + 8^2) = sqrt 100 = 10
so cosecant of C is 10/8 = 1.25
Alright, so 3f-g=4 and f+2g=5.
3f-g=4
f+2g=5
Multiplying the first equation by 2 and adding it to the second, we get 7f=13 and by dividing both sides by 7 we get f=13/7. Since f+2g=5, then we can plug 13/7 in for f to get 13/7+2g=5. Next, we subtract 13/7 from both sides to get 2g=3+1/7=22/7 (since 3*7=21 and 21+1=22). DIviding both sides by 2, we get 22/14=g. Plugging that into f/39g, we get (13/7)/(22*39/14)
= (13/7)/(858/14)
= (13/7)*(14/858)
=182/6006
= 91/3003 (by dividing both numbers by 2)
= 13/429 (by dividing both numbers by 7)
= 1/33 (by dividing both numbers by 13)
